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4 years ago

What experiment supported the nuclear model of the atom ?

Chemistry

2 answers:

Degger [83]4 years ago

5 0

Gold fold experiment replaced the plum pudding model

Pani-rosa [81]4 years ago

4 0

It the gold foil experiment

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a culinary student fills a 40ml container with 37.2 grams of vegetable oil.What is the density of the oil

Lynna [10]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 37.2 g

volume = 40 mL

We have

$density = \frac{37.2}{40} \\ = 0.93$

We have the final answer as

Hope this helps you

4 0

3 years ago

A reaction proceeds with 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. this is the equation of the reacti

den301095 [7]

The theoretical amount of each product obtained are:

1.57 moles of Mg(OH)₂
3.14 moles of NaClO₃

<h3>Balanced equation</h3>

Mg(ClO₃)₂ + 2NaOH —> Mg(OH)₂ + 2NaClO₃

<h3>How to determine the limiting reactant</h3>

From the balanced equation above,

1 mole of Mg(ClO₃)₂ reacted with 2 moles of NaOH

Therefore,

2.72 moles of Mg(ClO₃)₂ will react with = 2.72 × 2 = 5.44 moles of NaOH

From the calculation above, we can see that a higher amount (5.44 moles) of NaOH than what was given (3.14 moles) is needed to react completely with 2.72 moles of Mg(ClO₃)₂

Therefore, NaOH is the limiting reactant

<h3>How to determine the theoretical yield of Mg(OH)₂</h3>

From the balanced equation above,

2 moles of NaOH reacted to produce 1 mole of Mg(OH)₂

Therefore,

3.14 moles of NaOH will react to produce = 3.14 / 2 = 1.57 moles of Mg(OH)₂

Thus, the theoretical yield of Mg(OH)₂ is 1.57 moles

<h3>How to determine the theoretical yield of NaClO₃</h3>

From the balanced equation above,

2 moles of NaOH reacted to produce 2 mole of NaClO₃

Therefore,

3.14 moles of NaOH will also react to produce 3.14 moles of NaClO₃

Thus, the theoretical yield of NaClO₃ is 3.14 moles

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ4

8 0

2 years ago

what is the temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr if it occupies 13.3L at 55 degrees Celsius and 7

Rus_ich [418]

Answer:

3 °C

Explanation:

The pressure is constant, so this looks like a case where we can use Charles’ Law:

$\frac{ V_{1} }{T_{1}} = \frac{V_{2} }{T_{2}}$

Invert both sides of the equation.

$\frac{T_{1} }{V_{1}} = \frac{T_{2} }{V_{2}}$

Multiply both sides by <em>V</em>₂

$T_{2} = T_{1} \times \frac{V_{2} }{ V_{1} }$

<em>V</em>₁ = 13.3 L; <em>T</em>₁ = (55 + 273.15) K = 328.15 K

<em>V</em>₂ = 11.2 L; <em>T</em>₂ = ?

$T_{2} = \text{328.15 K} \times \frac{\text{11.2 L} }{\text{13.3 L}} = \text{276 K} = 3 ^{\circ}\text{C}$

8 0

3 years ago

What is the concentration (M) of a solution with a pH of 9.52 ?

masya89 [10]

Answer:

[H⁺] = 3.02 x 10⁻¹⁰M

Explanation:

Given parameters:

pH of the solution = 9.52

Unknown:

Concentration of the solution

Solution

There is a relationship between the pH and concentration of a solution.

pH = -log₁₀[H⁺]

The unknown here is [H⁺],

Now making it the subject of the formula

[H⁺] = Inverse log₁₀(-pH)

[H⁺] = Inverse log₁₀(-9.52)

[H⁺] = 3.02 x 10⁻¹⁰M

6 0

4 years ago

To conserve energy the genes in E. coli are ____

lianna [129]

d is ur answer in my opinion

3 0

3 years ago

Read 2 more answers