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3 years ago

Exact numbers 5600s measured by a stop watch

1 answer:

4 0

The time measured by a stopwatch is not an exact number. The number is limited by the precision of the instrument (the stopwatch) and it migh have been 56.004 instead of 56.00, and the stopwatch cannot shoe that. So, this is not an exact number.

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What is required to know the velocity of an object

Andreyy89

Answer:

n order to find the velocity of the moving object, you will need to divide the change in position by the change in time. Specify the direction moved, and you have the average velocity

8 0

3 years ago

In a lab in New York, Thomas and Nikola collected data over several trials. Thomas recorded his measurements as 10.0 A, 11 A, an

Anna11 [10]

Nikola's reading has a lower range and it is logical to conclude that his reading is more precise.

Explanation:

Precision is the ability to reproduce the same set of result from a measurement. The more repeatability a measurement is, the more precise it is.

From the given pool of data, it is easy to determine which set of data is more precise over the other.

Thomas measurements: 10.0 A, 11 A, and 8 A

Nikola measurements: 9.0 A, 9.2 A, 8.8 A

Using the range method, it is possible to find the precision in this pool of data.

Method and Solution:

Find the range of the sample:

Range = highest value - lowest value

Thomas measurement; Range = (11-8)A = 3.0A

Nikola measurement; Range = (9.2-8.8)A = 0.4A

Find the mean of the samples:

Mean of Thomas measurement = $\frac{10 + 11+ 8}{3}$ = $\frac{29}{3}$ = 9.7A

Mean of Nikola measurement = $\frac{9+ 9.2+ 8.8}{3}$ = $\frac{27}{3}$ = 9A

Now let us quote the range of value of the mean of each measurement:

Thomas 9.7±3.0A

Nikola 9.0± 0.4A

Nikola's reading has a lower range and it is logical to conclude that his reading is more precise.

Learn more:

mean calculation brainly.com/question/12068498

#learnwithBrainly

5 0

3 years ago

What will increase the salt concentration in seawater?

MA_775_DIABLO [31]

Answer:

Evaporation process

Explanation:

The evaporation process is responsible for the increase in the concentration of salt in the oceans or seawater.

Within the ocean there are certain places where there occurs little or no rainfall. The temperature in this region is relatively high and dry, due to which there occurs the process of evaporation. Because of the absence of rainfall, the rate of evaporation is higher in this region compared to the rate of precipitation. So when this process takes place, it eliminates the water quantity present in it, resulting in the formation of salts.

The salinity of the ocean increases because of the high rate of evaporation of the ocean water as well as forming of the sea ice.

8 0

4 years ago

Imagine you leave a bottle of something toxic to humans open overnight in a sealed laboratory.

IgorC [24]

Answer:

Argument: It is not Safe

Further support to the argument is given below.

Explanation:

Solution:

Argument: It is not Safe

First of all, we all know the ideal gas law:

PV = nRT

And the Boyle's Law states that , if the pressure is increased then, volume will decrease. and if the volume is increased then pressure will decrease.

V is inversely proportional to Pressure of the gas.

So, in this case, Let's suppose we have toxic solution of methyl alcohol in the bottle which is tightly closed. It means pressure in the bottle is high, hence the volume is less.

If in this scenario someone, leave the bottle open in the laboratory and as it is given that the level of solution will drastically decrease. It means it is volatile in nature and is converted into gaseous form and we know now that the open bottle has now less pressure. Hence the volume of the gas will be higher and now it can spread to every corner of the laboratory. And it is very dangerous.

3 0

3 years ago

a scientist is measuring the measuring the temperature change in a chemical compound. the temperature dropped 11 per hr from the

stepladder [879]

Answer:

$\large \boxed{134 \, ^{\circ}\text{C}}$

Explanation:

1. Calculate the temperature drop

$\text{Temperature drop} = \text{4 h} \times \dfrac{11 \,^{\circ}\text{C}}{\text{1 h}} = 44 \,^{\circ}\text{C}$

2. Calculate the original temperature

$\begin{array}{rcl}\text{Final Temperature} & = & \text{original temperature - temperature drop}\\90 ^{\circ}\text{C} & = & \text{original temperature - 44} \, ^{\circ}\text{C}\\\text{Original temperature}& = & \mathbf{134 \, ^{\circ}}\textbf{C}\\\end{array}\\\text{The original temperature was $\large \boxed{\mathbf{134 \, ^{\circ}}\textbf{C}}$}$

5 0

4 years ago