The answer is -0.22 for the total impact of velocity 1.1 seconds -5.0=-
Answer:
- Only the methyl ester of aspartame is sweet. True
- Amide bonds can be hydrolyzed under only acidic conditions. False
- The zwitterionic form of the amide bond is the most favored resonance form. True
- The phosphoric acid in soda hydrolyses the aspartame ester making it sweet. False
Explanation:
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Aspartame is obtained by combining phenylalanine and aspartic acid. Its main impurity is dicetopiperazine, which does not possess sweetening properties.
- Amide bonds can be hydrolyzed both under basic and acidic conditions.
- The zwitterionic form of the amide bond is the most favored resonance form. A zwitterion is an electrically neutral chemical compound, but it has formal positive and negative charges on different atoms, presenting high stability
- Phosphoric acid creates an acidic medium that improves the absorption of carbon dioxide, reducing the pressure generated by carbon dioxide and thus allowing bottleneck. Phosphoric acid has a bitter taste that is offset by the addition of sugar
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<span> a) AgNO3 (aq) + KCl (aq) --> AgCl (s) + KNO3 (aq) this is balanced chemical equation
</span><span>AgCl is the precipitate so we shall not split it
</span><span>Ag+(aq) + NO3 -(aq) + K+ (aq) + Cl-(aq) --> AgCl (s) + K+(aq) + NO3-(aq)
</span><span>Ag+ (aq) + Cl- (aq) ---> AgCl (s) after removing ions</span>
Answer is: <span> the equilibrium concentration of Br</span>₂ is 0,02 mol/L.<span>
</span>Chemical reaction: Br₂ + Cl₂ → 2BrCl.
Kc = 7,0.
c₀(Br₂) = 0,25 mol ÷ 3 L.
c₀(Br₂) = 0,083 mol/L.
c₀(Cl₂) = 0,55 mol ÷ 3 L.
c₀(Cl₂) = 0,183 mol/L.
Kc = c(BrCl)² ÷ c(Br₂) · c(Cl₂).
7 = (2x)² ÷ (0,083 mol/L - x) · (0,183 mol/L - x).
7 = 4x² ÷ (0,083 mol/L - x) · (0,183 mol/L - x).
Solve q<span>uadratic equation: x = 0,063 mol/L.
</span>c(Br₂) = 0,083 mol/L - 0,063 mol/L = 0,02 mol/L.
