The average rate of a reaction is a good approximation of an instantaneous rate when the concentration is measured during relatively brief time intervals.
At any point during such a little period, the average rate will be extremely near to the instantaneous rate. The average rate will differ from the instantaneous rates inside the period more when time intervals are longer.
The concentration change during a chosen time period is the average rate. When you take the measurements makes a difference.
The rate at a specific moment is known as the instantaneous rate. Finding the slope of the tangent to the concentration vs. time curve at that point yields the answer.
Learn more about comparison between average and instantaneous rate here brainly.com/question/17960561
#SPJ4
I believe the appropriate pair is O and S, Periodic table represents arrangements of elements ordered by their atomic number,physical and chemical properties. Both sulfur and oxygen are in the same group of the periodic table (group 6), they have a valency of 2, This means they have a greater similarity in chemical and physical properties.
<h3>
Answer: b) 0.250 mol</h3>
============================================
Work Shown:
Using the periodic table, we see that
- 1 mole of carbon = 12 grams
- 1 mole of oxygen = 16 grams
These are approximations and these values are often found underneath the atomic symbol. For example, the atomic weight listed under carbon is roughly 12.011 grams. I'm rounding to 2 sig figs in those numbers listed above.
So 1 mole of CO2 is approximately 12+2*16 = 44 grams. The 2 is there since we have 2 oxygens attached to the carbon atom.
-------------------
Since 1 mole of CO2 is 44 grams, we can use that to convert from grams to moles.
11.0 grams of CO2 = (11.0 grams)*(1 mol/44 g) = (11.0/44) mol = 0.250 mol of CO2
In short,
11.0 grams of CO2 = 0.250 mol of CO2
This is approximate.
We don't need to use any of the information in the table.
Answer:
neutrons are uncharged and electrons are negatively charged
I have a answer but I’m not sure of it