Water solubility of oxygen at 25oC and pressure = 1 bar is at 40 mg/L water. In air with a normal composition the oxygen partial pressure is 0.2 atm. This results in dissolution of 40 . 0.2 = 8 mg O2/L in water that comes in contact with air.
Answer:
D)subscript of C in molecular formula = n x subscript of C in empirical formula
Explanation:
THIS IS THE COMPLETE QUESTION BELOW;
.The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular formula and the empirical formula? a)<br /><br /> empirical formula mass / molecular mass = n<br /><br /> B) molecular mass = element mass / empirical formula mass ´ 100<br /><br /> c) subscript of H in empirical formula = 2  subscript of H in molecular formula<br /><br /> D) subscript of C in molecular formula = n  subscript of C in empirical formula<br /><br />
An empirical formula can be regarded as "shorten form" of a molecular formula. Instance of this is
A compounds CH4, C2H8, C4H12... with empirical formula of CH4. In this case a constant "n" represent the difference that exist between empirical formula and molecular formula, "n" which is a whole number, molecular formula is the numerator.
Therefore, subscript of C in molecular formula = n x subscript of C in empirical formula
In accordance with the Le Chatelier's Principle, when the concentration of the aluminum increases then the equilibrium would shift to the right. It will produce more products since there are more reactants available and also collision is more frequent.
Answer:
The answer to your question is:
Explanation:
Iron (III) ⇒ Iron (II)
Fe⁺³ + 1e⁻ ⇒ Fe⁺²
Answer:
The answer is 1.778*10^-9
Explanation:
Using the formula
pH = -log[H^+]
Since the pH of the solution has been given to be 8.75,
Therefore,
8.75= -log [H^+]
Let's take H^+ to be x
8.75= -log x
Let's look for x, since the log is in base 10
X = 10^-8.75
X = 1.778 * 10^ -9
Therefore, H^+ =1.778 *10^-9
