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Salsk061 [2.6K]
2 years ago
14

What is the molarity of a solution in which 175.8 grams of NaCl is dissolved in 1.5 L of water?

Chemistry
1 answer:
Sophie [7]2 years ago
8 0
175.8 g NaCl to moles:
(175.8 g)/(58.44 g/mol) = 3.008 mol NaCl

Molarity = moles of solute/volume of solution in liters

(3.008 mol NaCl)/(1.5 L) = 2.0 M.

The molarity of this solution would be 2.0 M.
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What is the molarity of a NaCl solution containing 9.0<br> moles of NaCl in 3.0 L of solution?
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Answer:

3 M

Explanation:

Molarity equation: M = n/v

n = moles of solute

v = liters of solution

9 moles of NaCl / 3 L

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I hope this was a satisfying answer. Have a great night!
8 0
3 years ago
A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing point depression o
Ludmilka [50]

Answer:

0.297 °C

Step-by-step explanation:

The formula for the <em>freezing point depression </em>ΔT_f is

ΔT_f = iK_f·b

i is the van’t Hoff factor: the number of moles of particles you get from a solute.

For glucose,

       glucose(s) ⟶ glucose(aq)

1 mole glucose ⟶ 1 mol particles     i = 1

Data:

Mass of glucose = 10.20 g

  Mass of water = 355 g

                 ΔT_f = 1.86 °C·kg·mol⁻¹

Calculations:

(a) <em>Moles of glucose </em>

n = 10.20 g × (1 mol/180.16 g)

  = 0.056 62 mol

(b) <em>Kilograms of water </em>

m = 355 g × (1 kg/1000 g)

   = 0.355 kg

(c) <em>Molal concentration </em>

b = moles of solute/kilograms of solvent

  = 0.056 62 mol/0.355 kg

  = 0.1595 mol·kg⁻¹

(d) <em>Freezing point depression </em>

ΔT_f = 1 × 1.86 × 0.1595

        = 0.297 °C

3 0
3 years ago
A carpet sells for 27.99 a square yard. What is the price of the carpet square per square meter ?
klio [65]
There are 9 square meters in one square yard so divide 27.99 by 9

27.99/9=3.11

one square meter is $3.11

I hope I've helped!
3 0
3 years ago
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