Answer:
see explaination
Explanation:
Molecular equation;
2Li3PO4(aq) + 3CaCl2(aq) >>>> Ca3(PO4)2(s) + 6LiCl(aq)
Total ionic equation; . Includes all ions ;
6Li^+(aq) + 2PO4^-3(aq) + 3Ca^+2(aq) + 6Cl^-(aq) >>>> Ca3(PO4)2(s) + 6Li^+(aq) + 6Cl^-(aq)
Net ionic equation; remove common ions from total ionic;
2PO4^-3(aq) + 3Ca^+2(aq) >>>> Ca3(PO4)2(s)
Carbon dioxide and water pretty sure
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<u>Answer:</u> The value of equilibrium constant for the net reaction is 11.37
<u>Explanation:</u>
The given chemical equations follows:
<u>Equation 1:</u> ![A+2B\xrightarrow[]{K_1} 2C](https://tex.z-dn.net/?f=A%2B2B%5Cxrightarrow%5B%5D%7BK_1%7D%202C)
<u>Equation 2:</u> ![2C\xrightarrow[]{K_2} D](https://tex.z-dn.net/?f=2C%5Cxrightarrow%5B%5D%7BK_2%7D%20D)
The net equation follows:
![D\xrightarrow[]{K} A+2B](https://tex.z-dn.net/?f=D%5Cxrightarrow%5B%5D%7BK%7D%20A%2B2B)
As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.
The value of equilibrium constant for net reaction is:

We are given:


Putting values in above equation, we get:

Hence, the value of equilibrium constant for the net reaction is 11.37
Water is the BL base if it accepted a proton from NH4.
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