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kap26 [50]
3 years ago
12

A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl

+ Ca(OH)2 mc013-1.jpg CaCl2 + 2H2O What was the molarity of the HCl solution? 0.375 M 1.50 M 3.00 M 6.00 M
Chemistry
2 answers:
Neko [114]3 years ago
4 0
The answer is D
6.00 M. I just took the test 
cluponka [151]3 years ago
3 0

The molarity  of the HCl  solution is   6.00M

<em>Calculation</em>

<em> 2HCl + Ca(OH)2→ CaCl2 +2H2O</em>

 Step 1:find the   moles of Ca(OH)2

 =  molarity  x volume

=  2l x 1.5 mol/l =  3 .00 moles


Step 2:use the  mole ratio  of HCl : Ca(OH)2 to calculate the moles of HCl

That is Ca(OH)2 :HCl  is 2:1 therefore the moles of HCl= 3.00 moles x2= 6.00 moles.


step 3: find the molarity of HCl

molarity  of HCl = moles of HCL /  volume  in liters of HCl

   = 6.00 moles/ 1  L = 6.00 M

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RoseWind [281]
Most organic compounds are made of just 4 elements, which are carbon, hydrogen, oxygen, and nitrogen. (I think, I am not sure)

Hope that helps!!!
8 0
3 years ago
Read 2 more answers
Given the equation C3H8(g) + O2(g) = CO2(g) + H2O(g) and that the enthalpies of formation for H2O(g) = -241.8 kJ/mol, CO2(g) = -
kari74 [83]

Answer: 72.4 kJ/mol

Explanation:

The balanced chemical reaction is,

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)  \Delta H=-2220.1kJ/mol

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_3H_8}\times \Delta H_{C_3H_8})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-2220.1=[(3\times -393.5)+(4\times -241.8)]-[(5\times 0)+(1\times \Delta H_{C_3H_8})]

\Delta H_{C_3H_8}=72.4kJ/mol

Therefore, the heat of formation of propane is 72.4 kJ/mol

7 0
3 years ago
If 4.35 grams of zinc metal react with 35.8 grams of silver nitrate, how many grams of silver metal can be formed and how many g
vaieri [72.5K]
The balanced chemical reaction is written as:

<span>Zn + 2AgNO3 = Zn(NO3)2 + 2Ag

To determine the grams of silver metal that is being produced, it is important to first determine which is the limiting reactant and the excess reactant from the given initial amounts. We do as follows:

4.35 g Zn ( 1 mol / 65.38 g ) ( 2 mol AgNO3 / 1 mol Zn ) = 0.1331 mol AgNO3 needed
35.8 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Zn / 2 mol AgNO3 ) = 0.1054 mol Zn needed

Therefore, the limiting reactant would be the zinc metal since it would be consumed completely in the reaction. The excess amount of AgNO3 would be:

0.2107 mol AgNO3 - 0.1331 mol AgNO3 = 0.0776 mol AgNO3 left ( 169.87 g / 1 mol ) = 13.19 g AgNO3 left

0.0665 mol Zn ( 2 mol Ag / 1 mol Zn) ( 107.9 g / 1 mol) = 14.3581 g Ag produced</span>
5 0
4 years ago
How does the average reaction rate differ from an instantaneous reaction rate?
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C because the average is receipt rate is how quickly
5 0
3 years ago
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2 Al + Fe2O3 = Al2O3 + 2 Fe + 850 kJ How many kJ are produced by 2 moles of Fe2O3? *
lorasvet [3.4K]

Answer:

1700 kj

Explanation:

The given reaction is exothermic reaction.

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂   →  CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂   →  CO₂ + 393 Kj/mol

Chemical equation:

2Al + Fe₂O₃     →    Al₂O₃ + 2Fe + 850 Kj

when one mole of Fe₂O₃  react 850 kj energy is produced.

when 2 moles react,

2 × 850 kj = 1700 kj

8 0
4 years ago
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