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TEA [102]
3 years ago
8

The atom in a sample of an element must contain nuclei with the same number of?

Chemistry
1 answer:
slava [35]3 years ago
7 0
Hey there! 

Answer: Protons 

The atom in a sample of an element must contain nuclei with the same number of protons. If the protons change in number, then the element will modify as well. 

Thank you!
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What force is the type of intermolecular force that would be present between molecules of Cl2 ?
KatRina [158]

Cl2 is nonpolar so it has to be only London dispersion force (LDF)

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3 years ago
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what grade is learning What amount of thermal energy (heat) in joules required to raise the temperature of 25 grams of water fro
blsea [12.9K]

Answer:

10425 J are required

Explanation:

assuming that the water is entirely at liquid state at the beginning , the amount required is

Q= m*c*(T final - T initial)

where

m= mass of water = 25 g

T final = final temperature of water = 100°C

T initial= initial temperature of water = 0°C

c= specific heat capacities of water = 1 cal /g°C= 4.186 J/g°C ( we assume that is constant during the entire temperature range)

Q= heat required

therefore

Q= m*c*(T final - T initial)= 25 g * 4.186 J/g°C * (100°C- 0°C) = 10425 J

thus 10425 J are required

7 0
3 years ago
The atomic weight of this radioactive element is equal to the produc of 7 and 14
earnstyle [38]

Answer: Krypton

Explanation:

7(14)=84

Krypton, if you look at the periodic table, has an atomic mass of approximately 84. It has a large nucleus, so while it is stable (due to its full octet) the nucleus is probably unstable due to repulsive forces between protons in the nucleus so is probably radioactive.

5 0
3 years ago
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What are things that cause change
inessss [21]

Explanation:

A catalyst means "something that causes activity,an event, or change." And usually,these events and changes are big.

I hope it's helpful!

5 0
2 years ago
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A researcher wants to make a solution of agcl and water at 75 °c. for solid agcl at 75°c, ksp = 1.5 x 10-5.
mars1129 [50]
A.)
dG = -(0.008314)(348K) (1.5 * 10-5)
dG = -(0.008314)(348K (-11.107)
dG = 32 kJ/mol (rounded from 32.14) 
--------
B.)
AgCl(s) >>>> Ag+ and Cl-
<span>Ksp = {Ag+}{Cl-} 
</span><span>1.5 * 10-5 = {Ag+}{Cl-}
</span>1.5 * 10-5 = {X}{X}
<span>X2 = 1.5 x 10-5 
</span>X={Ag+}{Cl-}
Sol / AgCl = 3.873E-3 litres/moles
<span>(3.873E-3 moles AgCl/Litre) (143.32 g AgCl / mol)= 0.56g AgCl</span>
7 0
3 years ago
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