Question

Write a net ionic equation that describes a slightly basic solution resulting from dissolving nac2h3o2 in water. Identify all of the phases in your answer.

Answer 1

Answer: The net ionic equation will be as follows.

     $CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)$

Explanation:

The chemical equation for the given reaction is as follows.

      $CH_{3}COONa(aq) + H_{2}O(l) \rightleftarrow CH_{3}COOH(aq) + NaOH(aq)$

We know that a strong acid or base will dissociate completely into a solvent whereas a weak acid or base dissociates partially into the solvent. Hence, the ionic equation will be as follows.  

$CH_{3}COO^{-}(aq) + Na^{+}(aq) H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + Na^{+}(aq) + OH^{-}(aq)$ Now, we will cancel the spectator ions from the above equation. Therefore, the net ionic equation will be as follows.

     $CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)$

or,  $C_{2}H_{3}O^{-}_{2}(aq) + H_{2}O(l) \rightleftharpoons HC_{2}H_{3}O_{2}(aq) + OH^{-}(aq)$