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ehidna [41]
3 years ago
6

3. Marissa thinks that there could be a pattern between the scale factor and perimeter of an image and its pre-image and between

the scale factor and area of an image and its pre-image.
(a) Determine the perimeter and area of the picture and the perimeter and area of the mat.
(b) Create a table that shows the perimeter and area of the picture and the perimeter and area of the mat for scale factors of 2, 3, and 4.
(I will give brainliest) 50 points!
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0

Answer:

Table

________________________________

Scale factor 3.

(-1-3,2+3) -->  A(-4,5)

(1+3,2+3) -->   B(4,5)

(1+3,-2-3) -->  C(4,-5)

(-1-3,-2-3) --> D(-4,-5)

(-2-3,3+3) -->  E(-5,6)

(2+3,3+3) -->   F(5,6)

(2+3,-3-3) -->  G(5,-6)

(-2-3,-3-3) --> H(-5,-6)

___________________________________

Scale factor 4

(-1-4,2+4) -->  A(-5,6)

(1+4,2+4) -->   B(5,6)

(1+4,-2-4) -->  C(5,-6)

(-1-4,-2-4) --> D(-5,-6)

(-2-4,3+4) -->  E(-6,7)

(2+4,3+4) -->   F(6,7)

(2+4,-3-4) -->  G(6,-7)

(-2-4,-3-4) --> H(-6,-7)

______________________________________________________

Second Image.

Scale Factor 2

Length = 6

Width = 8

Perimeter = 2(6+8)= 2(14) = 28

Area = 6 times 8 = 48.

Scale Factor 3

Length = 8

Width = 10

Perimeter = 2(8+10)= 2(18) = 36

Area = 8 times 10 = 80.

Scale Factor 4

Length = 10

Width = 12

Perimeter = 2(10+12)= 2(22) = 44

Area = 10 times 12 = 120.

_____________________________________________

Scale Factor 2

Length = 8

Width = 10

Perimeter = 2(8+10)= 2(18) = 36

Area = 8 times 10 = 80.

Scale Factor 3

Length = 10

Width = 12

Perimeter = 2(10+12)= 2(22) = 44

Area = 10 times 12 = 120.

Scale Factor 4

Length = 12

Width = 14

Perimeter = 2(12+14)= 2(26) = 52

Area = 12 times 14 = 168.

Step-by-step explanation:

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