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ehidna [41]
3 years ago
6

3. Marissa thinks that there could be a pattern between the scale factor and perimeter of an image and its pre-image and between

the scale factor and area of an image and its pre-image.
(a) Determine the perimeter and area of the picture and the perimeter and area of the mat.
(b) Create a table that shows the perimeter and area of the picture and the perimeter and area of the mat for scale factors of 2, 3, and 4.
(I will give brainliest) 50 points!
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0

Answer:

Table

________________________________

Scale factor 3.

(-1-3,2+3) -->  A(-4,5)

(1+3,2+3) -->   B(4,5)

(1+3,-2-3) -->  C(4,-5)

(-1-3,-2-3) --> D(-4,-5)

(-2-3,3+3) -->  E(-5,6)

(2+3,3+3) -->   F(5,6)

(2+3,-3-3) -->  G(5,-6)

(-2-3,-3-3) --> H(-5,-6)

___________________________________

Scale factor 4

(-1-4,2+4) -->  A(-5,6)

(1+4,2+4) -->   B(5,6)

(1+4,-2-4) -->  C(5,-6)

(-1-4,-2-4) --> D(-5,-6)

(-2-4,3+4) -->  E(-6,7)

(2+4,3+4) -->   F(6,7)

(2+4,-3-4) -->  G(6,-7)

(-2-4,-3-4) --> H(-6,-7)

______________________________________________________

Second Image.

Scale Factor 2

Length = 6

Width = 8

Perimeter = 2(6+8)= 2(14) = 28

Area = 6 times 8 = 48.

Scale Factor 3

Length = 8

Width = 10

Perimeter = 2(8+10)= 2(18) = 36

Area = 8 times 10 = 80.

Scale Factor 4

Length = 10

Width = 12

Perimeter = 2(10+12)= 2(22) = 44

Area = 10 times 12 = 120.

_____________________________________________

Scale Factor 2

Length = 8

Width = 10

Perimeter = 2(8+10)= 2(18) = 36

Area = 8 times 10 = 80.

Scale Factor 3

Length = 10

Width = 12

Perimeter = 2(10+12)= 2(22) = 44

Area = 10 times 12 = 120.

Scale Factor 4

Length = 12

Width = 14

Perimeter = 2(12+14)= 2(26) = 52

Area = 12 times 14 = 168.

Step-by-step explanation:

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Answer:

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.

Step-by-step explanation:

Function 1)

Determining rate of change for function 1:

x        1         2         3         4

y       5        8          11        14

Finding the rate of change or slope using the formula

Rate of change = m = [y₂-y₁] / [x₂-x₁]

Taking any two points, let say (1, 5) and (2, 8)

Rate of change = m = [8-5] / [2-1]

                                 = 3/1

                                  = 3

Therefor, the rate of change of function 1 = m = 3

using point-slope form to determine the function equation

y-y₁ = m (x-x₁)

where m is the rate of change or slope

substititng m = 3 and the point (1, 5)

y - 5 = 3(x - 1)

y - 5 = 3x-3

y = 3x-3+5

y = 3x + 2

Thus, equation of function 1 will be:

y = 3x + 2

Determining Initial Value for Function 1:

substituting x = 0 in the equation to determine the initial value

y = 3(0)+2

y = 0+2

y = 2

Therefore, the initial Value of function 1 will be: y = 2

Function 2)

Determining the rate of change for function 2:

Given the function 2

y\:=\:\frac{5}{3}x+3

comparing with the slope-intercept form of a linear function

y = mx+b     where m is the rate of change

so the rate of change of function 2 = m = 5/3

Determining Initial Value for Function 2:

substituting x = 0 in the equation to determine the initial value

y\:=\:\frac{5}{3}x+3

y\:=\:\frac{5}{3}\left(0\right)+3

y = 0+3

y = 3

Therefore, the initial Value of function 2 will be: y = 3

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.

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