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grandymaker [24]
2 years ago
8

Multivariable Calculus Question:

Mathematics
1 answer:
vovangra [49]2 years ago
3 0
f(2,-1)=2^2-(-1)^2=3

so we're considering the level curve

x^2-y^2=3

The tangent line to this curve at (2, -1) will be the value of \dfrac{\mathrm dy}{\mathrm dx} at this point. Differentiating yields

2x-2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac xy

and so the slope of the tangent would be \dfrac2{-1}=-2.

The tangent line then has equation

y-(-1)=-2(x-2)\implies y=-2x+3
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Step-by-step explanation:

Lets define a linear equation first.

A linear equation is an equation in which there is no variable with exponent greater than 1 or the degree of the equation is 1.

So,

<u>x + 12 = -8x + 10 - 2y</u>

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The equation is a linear equation because the degree of the equation is 1.

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The equation involve a term with exponent 2 which makes the degree of the equation 2 making it a quadratic equation

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Hence,

2x + 6y = 14y - 19x^2 + 12 is a non-linear equation

Keywords: Linear, quadratic

Learn more about equations at:

  • brainly.com/question/5102020
  • brainly.com/question/5147732

#LearnwithBrainly

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