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shtirl [24]
2 years ago
15

The cost of 3 markers and 2 pencils is $1.80. The cost of 4 markers and 6 pencils is $2.90. What is the cost of each item? Inclu

de appropriate units in your answer. :​
Mathematics
1 answer:
RideAnS [48]2 years ago
7 0
Let M = marker cost
Let P = pencil cost

3 markers and 2 pencils cost 1.80 ==> 3M + 2P = 1.80

4 markers and 6 pencils cost 2.90 ==> 4M + 6P = 2.90

Multiply the first equation by (-3) and add it to the second equation

-9M - 6P = -5.40
4M + 6P = 2.90

-5M = -2.50
M = 0.50

Plug this value for M into the 1st equation and solve for P

3*(0.50) + 2P = 1.80
1.50 + 2P = 1.80
2P = 0.30
P = 0.15

So a marker costs 50 cents and a pencil costs 15 cents
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An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
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Answer:

P(X\leq 1) = 0.331

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Given

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Required

Determine the probability of renting no more than 1 apartment

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P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

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P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
3 years ago
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