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shtirl [24]
3 years ago
15

The cost of 3 markers and 2 pencils is $1.80. The cost of 4 markers and 6 pencils is $2.90. What is the cost of each item? Inclu

de appropriate units in your answer. :​
Mathematics
1 answer:
RideAnS [48]3 years ago
7 0
Let M = marker cost
Let P = pencil cost

3 markers and 2 pencils cost 1.80 ==> 3M + 2P = 1.80

4 markers and 6 pencils cost 2.90 ==> 4M + 6P = 2.90

Multiply the first equation by (-3) and add it to the second equation

-9M - 6P = -5.40
4M + 6P = 2.90

-5M = -2.50
M = 0.50

Plug this value for M into the 1st equation and solve for P

3*(0.50) + 2P = 1.80
1.50 + 2P = 1.80
2P = 0.30
P = 0.15

So a marker costs 50 cents and a pencil costs 15 cents
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Am I correct? (Perfect Square Form)
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Answer:

(x -3 )^2 = 10

Step-by-step explanation:

Given

x^2 - 6x - 1 = 0

Required: Express as a perfect square

x^2 - 6x - 1 = 0

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x^2 - 6x - 1 +10= 0+10

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Expand

x^2 - 3x  - 3x+9= 10

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3 years ago
In the Itty Bitty High School, there are 85 students. There are 27 students who take French, 51 who take Geometry and 38 who tak
andrew-mc [135]

Answer:

58 students

Step-by-step explanation:

Given

Total = 85

French = 27

Geometry = 51

History = 38

None = 5

All = 2

Required

Students that take only 1 subjects

The attached image illustrates the question.

For French only (x), we have:

x + 7 -2+10-2+2=27

x + 15=27

Collect like terms

x =- 15+27

x =12

For Geometry only (y), we have:

y+10-2+15-2+2=51

y+23=51

Collect like terms

y=-23+51

y=28

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Collect like terms

z =-20+38

z =18

Students with one subject is then calculated as:

1\ subject = x+y+z

1\ subject = 12 + 28 + 18

1\ subject = 58

5 0
3 years ago
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Kazeer [188]

Answer:

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Step-by-step explanation:

Following what the problem mentions:

"eric is 70 inches tall"

Eric=70in

"pablo is as half as tall as eric"

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pablo=\frac{70in}{2}=35in

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annete=pablo+5.25in

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tino4ka555 [31]

Answer:

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Step-by-step explanation:

y+9 = ?

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