Answer:
I see no eaquations?
It should be matter=constant
Answer:
it is whatever the temperature is at 5(I cant seem to see it clearly)
Explanation:
Answer: a. 17.7 KJ/Mol
b. T=210K
Explanation:
Arsine, ash3 is a highly toxic compound used in the electronics industry for the production of semiconductors. its vapor pressure is 35 torr at – 111.95°c and 253 torr at – 83.6°c. using these data calculate.
the question isnt completely originally, but we could look at the likely derivation from the questions
(a) the standard enthalpy of vaporization
using the clausius clapeyron equation
In (PT1vap / PT2vap) = delta H (vap) / R ( (1/T1) - (1/T2) )
In (35Torr/253Torr) = delta H (vap) / 8.3145 ( (1/189.55) - (1/161.2) )
Therefore, Delta H (vap) = 17.7 KJ/Mol
b. Also the boiling point
What is the normal boiling point of arsine?
At the boiling point Pvap = atmospheric pressure = 1 atm=760 torr
substitution into the equation as stated in question 1
ln(760/253)=17700/8.314(1/189.55-1/T)
T=210K
Answer:
149,700,000 km (= 1.50 x 10⁸ km)
Explanation:
Given,
Speed of light, c = 300,000 km/s
Time Taken = 8 min 19 s = 499 seconds
Recall, Distance = Speed x Time
= 300,000 km/s x 499 s
= 149,700,000 km
= 1.50 x 10⁸ km
Answer: A. The reactants have higher potential energy, and energy is released.
Explanation:
ap3x