Kepler's third law of planetary motion states that:
"The ratio between the cube of the orbital radius of the planet and the square of the orbital period is constant". In formulas:
where r is the orbital radius and T the orbital period.
Since this ratio is constant for every planet, we see that when the orbital radius r is larger (i.e. when the planet is farther from the Sun), the orbital period T is larger: this means the planet takes more time to complete one revolution around the Sun, so it moves slower.
Therefore, the correct option is:
<span>A planet moves slowest when it is farthest from the sun.</span>
Answer: C
C. Place plastic around the metal wires, because electric charges
hardly move in plastic.
Answer:
D = 104.4 m
Explanation:
We are given two displacement vectors. One in north direction other in east direction. We know that north and east directions are perpendicular to each other. Hence, the displacements vectors are also perpendicular to each other. Therefore, there resultant can be found by using Pythagora's Theorem like rectangular components method.
D = √(Dₓ² + Dy²)
where,
D = Magnitude of vector sum of both displacements = ?
Dₓ = Magnitude of Displacement Vector in east direction = 30 m
Dy = Magnitude of Displacement Vector in North Direction = 100 m
Therefore,
D = √[(30 m)² + (100 m)²]
<u>D = 104.4 m</u>
It is made like the reflect in presence of magnetism. It gets deflected on earth towards north also because of a huge magnetism of earth.
The second one (4.1 kg ball)
This is because the mxv is greater than the other one.
For the 4.1kg ball, the force it’s moving on is 4.92N
As for the 3.2kg ball, it’s moving with a force of 0.9N. Much less than the other one.