Un cañón de electrones dispara electrones (q = -e, me = 9.1 × 10 -31 kg) hacia una placa metálica que está a 4.0 mm de distancia
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Answer:
The work done by the steam is 213 kJ.
Explanation:
Given that,
Mass = 5 kg
Pressure = 150 kPa
Temperature = 200°C
We need to calculate the specific volume
Using formula of work done
Where,R = gas constant
T = temperature
P = pressure
=Atmosphere pressure
m = mass
Put the value into the formula
Hence, The work done by the steam is 213 kJ.