Answer:
The answer to your question is Area = 37500 ft²
Step-by-step explanation:
Data
lawn 1 lawn 2
width = 550 ft width = 250 ft
Area = 181500 ft² Area = ?
Process
1.- Find the length of lawn 1
Area = length x width
-solve for length
length = Area/width
-Substitution
length = 181 500 ft²/ 550
-result
length = 330 ft
2.- Find the length of lawn 1 using ratios and proportions
550 : 330 :: 250 : x
x = (250 x 330) / 550
x = 150 ft
3.- Find the area of lawn 2
-Substitution
Area = 250 x 150
-Result
Area = 37500 ft²
You can use sum-product but the easiest way is to isolate x like this:
x^2 + 9x (-9x) = 0 (-9x)
x^2 = -9x
x^2 (/x) = -9x(/x)
x=-9
Answer:
(a) 1km
(b)80 fence panels
Step-by-step explanation:
(a) perimeter = 300+300= 600
200+200= + 400
=1000m
1km = 1000m
(b).
1panel = 2.5 m 1× 200÷2.5 = 80
=200m
Squareroot of 10 is 3.16
<span>(√5+√6) =4.68</span>
9514 1404 393
Answer:
b) 31%
Step-by-step explanation:
95% of the normal distribution is between Z values of ±1.96.
99% of the normal distribution is between Z values of ±2.576.
The change from a 95% interval to a 99% interval widens the range by ...
(2.576/1.96 -1) × 100% ≈ 31.4%
The width of the interval increases about 31%.
__
Compare the two attachments. The tail area of 0.05 means the central area is 0.95. Similarly, the tail area of 0.01 means the central area is 0.99.
_____
<em>Additional comment</em>
As always, when you're dealing with percentages, you need to understand what the base value is. Here, when we're talking about 95% and 99% confidence intervals, we're not talking about the numbers 0.95 and 0.99 and the increase from 0.95 to 0.99.
Rather we're talking about areas under the normal probability distribution curve, and the Z-values associated with those intervals. The change in interval width refers to the change in Z-values associated with the areas of 0.95 and 0.99.