Answer:
(a) 
(b) 
Solution:
As per the question:
Mass of the object, m = 1.30 kg
Length of the rod, L = 0.780 m
Angular speed, 
Now,
(a) To calculate the rotational inertia of the system about the axis of rotation:
Since, the rod is mass less, the moment of inertia of the rotating system and that of the object about the rotation axis will be equal:
(b) To calculate the applied torque required for the system to rotate at constant speed:
Drag Force, F = 
When you rub a balloon on a sweater, for example, some electrons come off and end up on the balloon. The fibers have lost electrons giving them a positive charge. The rubber gained electrons giving it a negative charge. ... The positively charged fibers are now attracted to the negatively charged balloon.
Answer:
a) m_ttoal = 40x
, b) m_total = 100X
, c) m_total = 400X
,
d) m_total = 1000 X
Explanation:
La magnificación o aumentos es el incremento de del tamaño de la imagen con respecto al tamaño original del objeto, en la mayoria del os sistema optico la magnificacion total es el producoto de la magnificación del objetivo por la magnificación del ocular
m_total = m_ objetivo * m=ocular
apliquemos esto a nuestro caso
1) m_total = 4 x * 10 x
m_ttoal = 40x
2) m_total = 10X * 10X
m_total = 100X
3)mtotal = 40X * 10X
m_total = 400X
4) m _totla = 100x * 10 X
m_total = 1000 X
en este ultimo caso para magnificación grandes es decalcificar el objeto
The formula is wavelength=speed÷frequency so if you do 15÷9 which equals 1.6
