<h2>Answer:</h2>
1.8 x 10⁻⁵J
<h2>Explanation:</h2>The energy (E) stored in a capacitor of capacitance, C, when a voltage, V, is supplied is given by;
E = x C x V² -------------------(i)
Now, from the question;
C = 2.00μF = 2.00 x 10⁻⁶F
V = 18.0V
Substitute these values into equation (i) as follows;
E = x 2.00 x 10⁻⁶ x 18.0
E = 1.8 x 10⁻⁵J
Therefore, the quantity of energy stored in the capacitor is 1.8 x 10⁻⁵J