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3 years ago

Doctors use radioactive sources as tracers for medical imaging. The table below shows the properties

Physics

1 answer:

Marysya12 [62]3 years ago

6 0

Answer:

Technetium.

Explanation:

Tc is a very versatile radioisotope, and is the most commonly used radioisotope tracer in medicine. It is easy to produce in a technetium-99m generator, by decay of 99Mo. ... Tc decays by gamma emission, with a half-life: 6.01 hours.

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The spinning of earth on its axis causes the apparent rising and setting of the

rodikova [14]

Sun, moon, and some stars

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3 years ago

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A 125 W motor accelerates a block along a level, frictionless surface at an average speed of 5.0

Lelu [443]

Answer:

25N

Explanation:

Given parameters:

Power of the motor = 125W

Average speed = 5m/s

Unknown:

Force supplied to the motor = ?

Solution:

Work done is the force applied to move a body through a particular distance;

Work done = Force x distance

Also,

Work done = Power x time

So;

Force x distance = Power x time

since force is the unknown;

Force = $\frac{Power x time}{distance}$

Speed = $\frac{distance }{time}$

Force = $\frac{Power}{speed}$

Now solve;

Force = $\frac{125}{5}$ = 25N

3 0

3 years ago

What would be the y-component of a velocity vector that had a

valentina_108 [34]

Answer:

18.5 m/s

Explanation:

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6 0

3 years ago

You must exert a force of 4.5 N on a book to slide it across a table. If you do 2.7J

hoa [83]

Answer: 0.6m

Explanation:

Given that:

force = 4.5 N

Work done = 2.7J

Distance moved by the book = ?

Since work is done when force is applied on an object over a distance, apply the formula:

work = force x distance

2.7J = 4.5N x distance

Distance = (2.7J / 4.5N)

Distance = 0.6 m

Thus, the book was moved 0.6 metres far

3 0

3 years ago

A model air rocket with a mass of 50.g is free to travel along a horizontal track. It begins from rest. After 2.0s, the rocket h

katen-ka-za [31]

Answer:

$v_r=5.89\ m.s^{-1}$

Explanation:

Given:

mass of rocket, $m_r=50\ g$

time of observation, $t=2\ s$

mass lost by the rocket by expulsion of air, $m_a=10\%\ of m_r=5\ g$

velocity of air, $v_a=53\ m.s^{-1}$

<u>Now the momentum of air will be equal to the momentum of rocket in the opposite direction: </u>(Using the theory of elastic collision)

$m_a.v_a=(m_r-m_a)\times v_r$

$5\times 53=(50-5)\times v_r$

$v_r=5.89\ m.s^{-1}$

7 0

3 years ago