Well, they're not quite the way Newton expressed it, but out of all this mess of statements, there are two that are correct AND come from Newton's 2nd Law of Motion:
<em>-- The smaller the mass of an object, the greater the acceleration of that object when a force is applied. </em>
<em>-- The greater the force applied, the greater the acceleration.</em>
For the <u><em>other </em></u>statements in the question:
-- <em>Every reaction is equal to the force applied.</em> True; comes from Newton's <u><em>3rd</em></u> law of motion.
-- <em>Forces are balanced when they are equal and opposite.</em> True; kind of a definition, not from Newton's laws of motion.
-- <em>An object at rest or in motion will remain at rest or in motion unless acted upon by an unbalanced force.
</em> True; comes from Newton's <em><u>1st </u></em>law of motion.
Explanation:
(a) Given:
Δx = 150 m
v₀ = 27 m/s
v = 54 m/s
Find: a
v² = v₀² + 2aΔx
(54 m/s)² = (27 m/s)² + 2a (150 m)
a = 7.29 m/s²
(b) Given:
Δx = 150 m
v₀ = 0 m/s
a = 7.29 m/s²
Find: t
Δx = v₀ t + ½ at²
150 m = (0 m/s) t + ½ (7.29 m/s²) t²
t = 6.42 s
(c) Given:
v₀ = 0 m/s
v = 27 m/s
a = 7.29 m/s²
Find: t
v = at + v₀
27 m/s = (7.29 m/s²) t + 0 m/s
t = 3.70 s
(d) Given:
v₀ = 0 m/s
v = 27 m/s
a = 7.29 m/s²
Find: Δx
v² = v₀² + 2aΔx
(27 m/s)² = (0 m/s)² + 2 (7.29 m/s²) Δx
Δx = 50 m
Answer:
1160 ohm
Explanation:
We are given that
R'=580 ohm
Current=3 I
We have to find the resistance of the circuit.
Let R be the resistance of circuit.
In parallel
Using the formula
In parallel combination,Potential difference across each resistance remains same.
Using the formula
Answer:
16
Explanation:
6+10=16
the box will go forward but it will be a little harder.
