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aivan3 [116]
3 years ago
15

Daniel can by a particular brand of juice in a 6 ounce bottle or a 10 ounce bottle the juice in a 10 ounce bottle contains 150 c

al calories how many calories are in a 6 ounce bottle
Mathematics
1 answer:
olasank [31]3 years ago
7 0

Answer: There are 90 calories in a 6-ounce bottle.

Step-by-step explanation:

We assume that the quantity of juice in the bottle is directly proportional to the number of calories it contains.

Given: 10 ounces of juice has 150 calories.

i.e. 1 ounce of juice has \dfrac{150}{10} calories.

i.e. 1 ounce of juice has 15 calories.

Now, In 6 ounce of juice, the number if calories = 15 x 6 = 90 calories

Hence, there are 90 calories in a 6-ounce bottle.

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Answer:

-17

Step-by-step explanation:

first find g(5) = -2(5)+5 = -5

then f(-5) = 4(-5)+3 = -17

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Amelia is using substitution to determine if 8 is a solution to the equation. Complete the statements. 6a = 42 for a = 8 First,
Tju [1.3M]

Amelia must substitute 8 for the variable using parentheses. To simplify, Amelia must multiply 8 by 6. 8 is not a solution of the equation.

<h3>What is algebraic expression?</h3>

Algebraic expression are the expression which consist the variables, coefficients of variables and constants.

The algebraic expression are used represent the general problem in the mathematical way to solve them.

Amelia is using substitution to determine if 8 is a solution to the equation.  The equation which is Amelia is solving  for a = 8 is,

6a = 42

First, Amelia must substitute 8 for the variable using parentheses as,

6(8) = 42

To simplify, Amelia must. multiply 8 by 6.

48 \neq 42

The left hand side of the eqqation is not equal to the right hand side. Thus, 8 is not a solution of the equation.

Thus, Amelia must substitute 8 for the variable using parentheses. To simplify, Amelia must multiply 8 by 6. 8 is not a solution of the equation.

Learn more about the algebraic expression here;

brainly.com/question/2164351

4 0
2 years ago
What is one possible solution for the triangle below?
elixir [45]
Answer:

segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°

Explanation:

1) Given two side lenghts and one angle you can use sine law:

\frac{sinA}{a} = \frac{sinB}{b} = \frac{sinC}{c}

2) Using the sides with length 43 in and 40in, and the corresponding opposite angles, Z and 68°, that leads to:

\frac{sinZ}{43} = \frac{sin68}{40}

From which you can clear sinZ and get:

sinZ = 43 × sin(68) / 40 = 0.9967

⇒ Z = arcsine(0.9967) ≈ 85.36°


3) The third angle can be determined using 85.36° + 68° + X = 180°

⇒ X = 180° - 85.36° - 68° = 26.64°.

4) Finally, you can apply the law of sine to obtain the last missing length:

\frac{x}{sin(26.64)} = \frac{40}{sin(68)}

From which: x = 40 × sin(26.64°) /  sin(68°) = 19.34 in

The answer, then is:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°
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