False. because.....
the equation of a circle is (x-h)^2 + (y-k)^2 = r^2 and the center is (h,k)
if the center of a circle is (-5, -13) substitute the values into the equation
so....(x- -5)^2 + (y- -13)^2 = r^2 which is (x+5)^2 + (y+13)^2 = r^2
in this case, because you are only asking about the center of the circle from the equation the 81 or radius of the circle doesn't matter.
What's 1/3 of 12?
Mulitply 1/3 times 12 = 4
Nita uses 4 eggs.
Answer: 24 and 104
Step-by-step explanation:
Answer:
<u>y = w and ΔABC ~ ΔCDE</u>
Step-by-step explanation:
Given sin(y°) = cos(x°)
So, ∠y + ∠x = 90° ⇒(1)
And as shown at the graph:
ΔABC is aright triangle at B
So, ∠y + ∠z = 90° ⇒(2)
From (1) and (2)
<u>∴ ∠x = ∠z </u>
ΔCDE is aright triangle at D
So, ∠x + ∠w = 90° ⇒(3)
From (1) and (3)
<u>∴ ∠y = ∠w</u>
So, for the triangles ΔABC and ΔCDE
- ∠A = ∠C ⇒ proved by ∠y = ∠w
- ∠B = ∠D ⇒ Given ∠B and ∠D are right angles.
- ∠C = ∠E ⇒ proved by ∠x = ∠z
So, from the previous ΔABC ~ ΔCDE by AAA postulate.
So, the answer is <u>y = w and ΔABC ~ ΔCDE</u>
