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natima [27]
3 years ago
10

A factory ships bottles in large boxes. Each box contains 2340 bottles. If the factory ships 28 boxes, how many bottles will the

y ship altogether?
Mathematics
2 answers:
Marina CMI [18]3 years ago
4 0

Answer:

65,520

Step-by-step explanation:

hope this is helpful

kodGreya [7K]3 years ago
4 0

Answer:

If each box has 2,340 bottles and they shipped 28 boxes then they should have shipped a total of 62,520 bottles altogether.

Step-by-step explanation:

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Simplify the following equation
morpeh [17]

Answer:

3x - 2

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Fifteen more than four times a number is equal to the difference between 191 and four times the number. Find the number.
Semenov [28]

Answer:

The number would be 22.

Step-by-step explanation:

In order to solve for the number, we need to make both statements into numerical statements.

Fifteen more than four times a number = 15 + 4x

difference between 191 and four times the number = 191 - 4x

Now we set them equal to each other.

15 + 4x = 191 - 4x -----> Add 4x to each side

15 + 8x = 191 ------> Subtract 15 from both sides

8x = 176 -------> Divide by 8

x = 22

5 0
3 years ago
The science club at Jersey High School is sponsoring a dance to raise money for their spring project. They will charge $4 per st
Dennis_Churaev [7]

Answer: 195

Step-by-step explanation:

Cost per student = $4

Total number who attended = n

The cost of the total of student who attended will be cost per student multiplied by the total number of students, that is

Total cos = 4n

Since, they are to pay $140 , for publicity, then the total cost becomes

T = 4n - 140

From the last statement

4n - 140 ≥ 640

4n ≥ 640 + 140

4n ≥780

n ≥ 780/4

n ≥ 195

That means at least 195 students must attend if the science club is to earn at least $ 640

6 0
3 years ago
Find the greatest number that divides451, 328 and 673 leaving 1, 4 and 1,respectively as remainders.
Vesna [10]

You're looking for the largest number <em>x</em> such that

<em>x</em> ≡ 1 (mod 451)

<em>x</em> ≡ 4 (mod 328)

<em>x</em> ≡ 1 (mod 673)

Recall that

<em>x</em> ≡ <em>a</em> (mod <em>m</em>)

<em>x</em> ≡ <em>b</em> (mod <em>n</em>)

is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly

1 ≡ 4 (mod 41)

is not true.

So there is no such number.

4 0
3 years ago
Find the area of a compound shape<br><br> Can you please explain
gtnhenbr [62]

Answer:

A=292.53~m^2

Step-by-step explanation:

<u>Area of a Compound Shape</u>

The shape shown in the image is made of two shapes: Half a circle of radius 8 m and a triangle of base 24 m and height 16 m.

The area of a circle of radius r is:

A_c = \pi r^2

The area of a triangle of base b and height h is:

\displaystyle A_t=\frac{b.h}{2}

Calculate the area of the circle:

A_c = \pi 8^2

A_c = 64\pi

Area of half the circle:

A_c/2 = 32\pi~m^2

Area of the triangle:

\displaystyle A_t=\frac{24\cdot 16}{2}

A_t=192~m^2

The area of the shaded shape is:

A=32\pi~m^2+192~m^2

Substituting the value of pi:

\mathbf{A=292.53~m^2}

4 0
3 years ago
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