Answer:
-----×1/72
Step-by-step explanation:
The <em>order of operations</em> says do these operations in order left to right. Please note that ÷ means the same as / unless you define it otherwise in your problem statement.
If you intend the ÷ symbol to be used to indicate everything to its left is divided by everything to its right, it is appropriate to use parentheses for that grouping, as in ...
(-----×1/4)÷(6×3/9) = (-----×1/4)÷2 = -----×1/8
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Here, we're going to evaluate what you have written according to the usual rules as described above.
(-----×1/4)÷6×3/9 = -----×1/24×3/9 = -----×(3/24)/9
= -----×1/8/9
= -----×1/72
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<em>Comment on the arithmetic</em>
Fractions are multiplied and divided in the usual way:
a/b×c = (a×c)/b
a/b/c = (a/b) × (1/c) = a/(b×c)
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<em>Comment on fractions and parentheses</em>
Please note that parentheses are required on any numerator or denominator that consists of anything other than a single number or variable. (The exception is the case where the numerator is a product, because a·b/c = (a·b)/c with or without the parentheses.)
Answer:
286 in³
Step-by-step explanation:
7×5 = 35
35×2 = 70in
9×5 = 45
45×2 = 90in
9×7 = 63
63×2 = 126in
70+90+126
=286in³
in plain and short, to graph an inequality, we first graph its EQUALITY graph, and then we do the shading.
so to graph y > x + 3, we first graph y = x + 3, which is just a line, and then do a true/false check on a point to see which side we shade.
let's hmmm check the point say (0,2), x = 0, y = 2.
y > x + 3
2 > 0 + 3
2 > 3 <--- is that true? is 2 really larger than 3? nope, so is false.
that simply means that the point (0, 2) is on the false area, so that's the area we do NOT shade, so <u>we shade the other side</u>.
y > x + 3, means "y" is greater than or larger than that line, but not equals, larger not equal, meaning the values on the borderline are not included, so the line is a dashed line.
check the picture below.
. The series is divergent. To see this, first observe that the series ∑ 1/kn for n = 1 to ∞ is divergent for any integer k ≥ 2.
Now, if we pick a large integer for k, say k > 100, then for nearly all integers n it will be true that 1 > cos(n) > 1/k. Therefore, since ∑ 1/kn is divergent, ∑ cos(n)/n must also be divergent The *summation* is divergent, but the individual terms converge to the number 0.<span>by comparison test since cosn/n <= 1/n is convergent
and 1/n is divergent by harmonic series
so the series is conditionally converget </span>
Let l, t, b represent the numbers of lions, tigers, bears, respectively.
2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals
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The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
