Assuming you pick 3 students at random, The probability that at least two plan on attending college is 84%.
<h3>Probability</h3>
Using Binomial Distribution
Given:
n = 3
p = 0.75
q = 1-0.95 = 0.25
Hence:
P[≥2] = P[2] + P[3]=(3c2 ×0.75²×0.25) + 0.75³
P[≥2] = P[2] + P[3]=0.421875+0.421875
P[≥2] = P[2] + P[3]=0.84375×100
P[≥2] = P[2] + P[3]=84% (Approximately)
Inconclusion the probability that at least two plan on attending college is 84%.
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120 = 15% x
15% = 0.15
x = 120 / 0.15 = 800
Answer:
A recent report estimated that 25% of all college students in the United States have a sexually transmitted disease (STD). The director of the campus health center believes that the proportion of students with STDs is higher at their campus.
According to the American Heart Association guidelines, the daily maximum amount of sugar a teenager should have is 4 teaspoons. The parents of a local high school have expressed concerns that the average daily sugar intake of their students is higher than these guidelines and have been pressuring school officials to limit unhealthy snack and beverage choices offered in the cafeteria and student store.
Step-by-step explanation:
The first two researches involve the single sample compared to mean of population.
The 3rd and 4th research involves comparing samples of men and women that is two individual groups.
Answer:
42,008
Step-by-step explanation:
Answer:
at 2/3 seconds
Step-by-step explanation:
S1(t) = t³ + 2
Average speed, dS1/dt = 3t²
S2(t) = t²
Average speed, dS2/dt = 2t
The distance between the objects is
dS1/dt - dS2/dt
= 3t² - 2t
The time the distance between the two object is at minimum is when the distance is 0
That is, when
3t² - 2t = 0
t(3t - 2) = 0
t = 0 or 3t - 2 = 0
t = 0 or t = 2/3