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hammer [34]
4 years ago
8

Write the sentence as an​ equation, using x as the variable. Then find the solution of the equation from the set of integers bet

ween minus12 and​ 12, inclusive. The quotient of a number and 4 is negative 1.
Mathematics
1 answer:
Inessa05 [86]4 years ago
4 0

Answer:

The solution of given equation is x = -4

Step-by-step explanation:

We are given the following in the question:

Let x be the variable such that

x \in (-12,12)

Relation:

The quotient of a number and 4 is negative 1

We can write the equation as:

\dfrac{x}{4} = -1

Solution:

\dfrac{x}{4} = -1\\\\\Rightarrow x = 4\times -1\\\Rightarrow x = -4

Thus, the solution of given equation is x = -4

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Find number of sides of a regular polygon if each of its exterior angle is 36.​
irinina [24]

Answer:

10 sides,that is, a decagon or 10gon

Step-by-step explanation:

If the exterior angle is 36° then numbers of sides=

36 = \frac{360}{n}

Therefore

n=360°÷36°=10

4 0
2 years ago
Read 2 more answers
Solve each equation 2n-5=21
aleksklad [387]
2n-5=21
add 5 to both sides
2n=26
divide both sides by 2
n=13

I hope I helped! :)
4 0
3 years ago
Solve triangle d, angle F and angle E when e=10, d=16.4, f=13, angle D=50
vodomira [7]

Answer:

P=a+b+c

the given triangle using the Law of Sines. Round lengths to the nearest tenth and angle measurements to the nearest degree.

5 0
2 years ago
Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?
worty [1.4K]

Answer:

4

Step-by-step explanation:

(x+y+z)(xy+xz+yz)=18 Equation 1

x^2(y+z)+y^2(x+z)+z^2(x+y)=6 Equation 2

What is the value of xyz where each variable represents a real number?

Let's expand equation 1:

(x+y+z)(xy+xz+yz)=18

x(xy)+x(xz)+x(yz)+y(xy)+y(xz)+y(yz)+z(xy)+z(xz)+z(yz)=18

Simplify each term if can:

x^2y+x^2z+xyz+y^2x+xyz+y^2z+xyz+z^2x+z^2y=18

See if we can factor a little to get some of the left hand side of equation 2:

The first two terms have x^2 and if I factored x^2 from first two terms I would have x^2(y+z) which is the first term of left hand side of equation 2.

So let's see what happens if we gather the terms together that have the same variable squared together.

x^2y+x^2z+y^2x+y^2z+z^2y+z^2x+xyz+xyz+xyz=18

Factor the variable squared terms out of each binomial pairing:

x^2(y+z)+y^2(x+z)+z^2(y+x)+xyz+xyz+xyz=18

Replace the sum of those first three terms with what it equals which is 6 from the equation 2:

6+xyz+xyz+xyz=18

Combine like terms:

6+3xyz=18

Subtract 6 on both sides:

3xyz=12

Divide both sides by 3:

xyz=4

4 0
3 years ago
Help needed ASAP!!!!!!!
alekssr [168]

Answer: 4 is 110 degrees  and 3 and 1 is 70 degrees.

Step-by-step explanation: 4 is equal to 2 so 4 is 110 degrees 4

110 x 2 = 220  360 - 220 = 140/2 = 70 so 3 and 1 = 70 degrees

8 0
3 years ago
Read 2 more answers
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