Simplify x^2-9/x^2+x-12
1 answer:
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Answer:
Option B
Step-by-step explanation:
Given: all the four-digit numbers are formed using the digits 1, 2, 3, and 4 such that no digit is used twice
To find: probability that number chosen lies between 2000 and 3000
Solution:
Probability refers to chances of occurring of some event.
Total number of numbers formed using digits 1, 2, 3, and 4 =
Numbers between 2000 and 3000 start with 2. So, first digit is fixed as 2. For remaining three digits, possibilities are 4, 3, 1
So, total number of numbers lie between 2000 and 3000 =
Probability that number chosen lies between 2000 and 3000 = total number of numbers lie between 2000 and 3000/Total number of numbers formed using digits 1, 2, 3, and 4 = 6/24 = 1/4
In percentage form, Probability that number chosen lies between 2000 and 3000 =