All because -2.22 is a real number, it’s a rational number because it can stop and a integer because it’s negative
Answer:
The Probability of exactly one tag being lost, in terms of π is ![2\pi(1-\pi)-\pi^2(1-\pi)^2](https://tex.z-dn.net/?f=2%5Cpi%281-%5Cpi%29-%5Cpi%5E2%281-%5Cpi%29%5E2)
Step-by-step explanation:
Using the tree diagram attached to the bottom of this answer, you can see that the probability of only one tag being lost is the union of the probability of the left tag being lost when the right one is not lost and the probability of the right tag being lost when the left one is not lost.
Probability of losing only the right tag:
![P(C2|\frac{}{C1})=P(C2)*\frac{}{P(C1)}=\pi*(1-\pi)](https://tex.z-dn.net/?f=P%28C2%7C%5Cfrac%7B%7D%7BC1%7D%29%3DP%28C2%29%2A%5Cfrac%7B%7D%7BP%28C1%29%7D%3D%5Cpi%2A%281-%5Cpi%29)
Probabilty of losing only the left tag:
![P(C1|\frac{}{C2})=P(C1)*\frac{}{P(C2)}=\pi*(1-\pi)](https://tex.z-dn.net/?f=P%28C1%7C%5Cfrac%7B%7D%7BC2%7D%29%3DP%28C1%29%2A%5Cfrac%7B%7D%7BP%28C2%29%7D%3D%5Cpi%2A%281-%5Cpi%29)
Now, to unite those two probabilities, we use basic probability properties:
∪
∩![P(C2|\frac{}{C1}))](https://tex.z-dn.net/?f=P%28C2%7C%5Cfrac%7B%7D%7BC1%7D%29%29)
Since the events are independent:
∩![P(C2|\frac{}{C1})=P(C1|\frac{}{C2})*P(C2|\frac{}{C1})](https://tex.z-dn.net/?f=P%28C2%7C%5Cfrac%7B%7D%7BC1%7D%29%3DP%28C1%7C%5Cfrac%7B%7D%7BC2%7D%29%2AP%28C2%7C%5Cfrac%7B%7D%7BC1%7D%29)
So, the union becomes:
∪![P(C1|\frac{}{C2})=P(C1|\frac{}{C2})+P(C2|\frac{}{C1})-P(C1|\frac{}{C2})*P(C2|\frac{}{C1})](https://tex.z-dn.net/?f=P%28C1%7C%5Cfrac%7B%7D%7BC2%7D%29%3DP%28C1%7C%5Cfrac%7B%7D%7BC2%7D%29%2BP%28C2%7C%5Cfrac%7B%7D%7BC1%7D%29-P%28C1%7C%5Cfrac%7B%7D%7BC2%7D%29%2AP%28C2%7C%5Cfrac%7B%7D%7BC1%7D%29)
Replacing:
![=\pi(1-\pi)+\pi(1-\pi)-\pi^2(1-\pi)^2=2\pi(1-\pi)-\pi^2(1-\pi)^2](https://tex.z-dn.net/?f=%3D%5Cpi%281-%5Cpi%29%2B%5Cpi%281-%5Cpi%29-%5Cpi%5E2%281-%5Cpi%29%5E2%3D2%5Cpi%281-%5Cpi%29-%5Cpi%5E2%281-%5Cpi%29%5E2)
You would use the A=Pe^rt equation here. A (total amount)= P (initial amount) e^r(rate)x t(time). Here is the equation for you to plug into your calculator. A=350e^0.45x10. The answer is..31505.99596
Answer:
3
Step-by-step explanation:
Add up the exponents of the variables
5xyz = 1+1+1 = 3
The degree is 3
5
−
2
x
−
2
x
−
2
5−
x
2
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x−2
2