QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
let x = orginal price of the shorts
$21 = x(100%-20%) * 1.05
$21 = x(80%) * 1.05
$21 = 0.8x * 1.05
Subtract 1.05 from both sides
$19.95 = 0.8x
Divide 0.8 from both sides
$24.9375 = x
So the orginal price of the shorts are about $24.94
I'm not following. What's the question?
Answer:
the correct answer would be 6 inches.
Step-by-step explanation:
12*.5=6
