Ask question

Ask question

All categories

3 years ago

7

Alayna parks her car in a lot that charges by the quarter hour. The table shows the parking fee, in dollars, with respect to the

time, in hours. Time (hours) 0.25 0.5 0.75 1 1.25 1.5 Parking Fee $0.50 $1.00 $1.50 $2.00 $2.50 $3.00 Time is the variable and should be placed on the . Parking fee is the variable and should be placed on the

1 answer:

riadik2000 [5.3K]3 years ago

7 0

Answer:

time should be placed on the independent/y-axis

parking fee should be placed on the dependent/x-axis

Step-by-step explanation:

good luck.

give me brainliest please:)

You might be interested in

2(5x + 7) = 34<br><br> Someone help me

Pepsi [2]

Answer:

x = 2

Step-by-step explanation:

2(5x + 7) = 34

10x + 14 = 34

10x = 34 - 14

10x = 20

x = 20/10

x = 2

7 0

3 years ago

Read 2 more answers

In a recipe for pizza sauce, the ratio of cans of tomatoes to teaspoons of oregano is 1:6. How many teaspoons of oregano do you

irina1246 [14]

Answer:

48 teaspoons of Oregano

Step-by-step explanation:

Ratio is given as:

Cans of tomatoes : Teaspoons of Oregano

1 : 6

Hence:

1 can of tomatoes = 6 teaspoons of Oregano

8 can of tomatoes = x teaspoons

Cross Multiply

x = 8 × 6 teaspoons

x = 48 teaspoons of Oregano

3 0

3 years ago

Pete's monthly housing budget is $2,250. His monthly costs are $215.75 for insurance, $143.50 for utilities, and $273 for taxes.

kogti [31]

Answer should be b hope it helps

4 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

Fill in the missing part of each product in order to make the equation into an identity.

kumpel [21]

Answer:

(2x^2+7)

Step-by-step explanation:

5x^3 * 2x^2 = 10x^5

5x^3 * 7 = 35x^3

7 0

3 years ago