Answer:
The answer to your question is: 85°
Step-by-step explanation:
Data
m∠ xyz = 2m∠x - 9
m∠w = 38°
Process
∠x = (∠xyz + 9) / 2
∠ y = 180 - ∠xyz
∠w + ∠y + ∠x = 180
Substitution 38 + (180 - ∠xyz) + (∠xyz + 9) / 2 = 180
76 + 360 - 2∠xyz + ∠xyz + 9 = 360
Simplify
85 - 2∠xyz + ∠xyz = 0
85 = ∠ xyz
Step-by-step explanation:
−2x+5y=−15 and 5x+2y=−6
Rewrite equations:
−2x+5y=−15;5x+2y=−6
Step: Solve−2x+5y=−15for x:
−2x+5y=−15
−2x+5y+−5y=−15+−5y(Add -5y to both sides)
−2x=−5y−15
−2x−2=−5y−15−2(Divide both sides by -2)
x=52y+152
Step: Substitute52y+152forxin5x+2y=−6:
5x+2y=−6
5(52y+152)+2y=−6
292y+752=−6(Simplify both sides of the equation)
292y+752+−752=−6+−752(Add (-75)/2 to both sides)
292y=−872
292y292=−872292(Divide both sides by 29/2)
y=−3
Step: Substitute−3foryinx=52y+152:
x=52y+152
x=52(−3)+152
x=0(Simplify both sides of the equation)
Answer:
x=0 and y=−3
Answer:
Step-by-step explanation:
Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1) eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
Dividing by coefficient other than +1
