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andrew11 [14]
3 years ago
5

What's the distance between earth and Saturn?​

Physics
2 answers:
svet-max [94.6K]3 years ago
7 0
996.39 million mi is how far the earth is from Saturn
PilotLPTM [1.2K]3 years ago
3 0

Answer:

the answer is 996.39 million miles

from Earth to Saturn

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I have the freedom of speech guaranteed by the 1st Amendment in the US Constitution; can I say whatever I want, whenever I want?
denis23 [38]

Answer:

No.

Explanation:

Even though it's called free speech, it really isn't free. You can't say certain things in public or on social media because people are too sensitive these days to handle the truth about something. You can, however, say what you want in a book or a protest with like-minded people because you really can't get in trouble for supporting whatever you want.

Hope this helps!

5 0
3 years ago
What is newton's third law second law first law ?​
sergeinik [125]

Answer:

first law: an object remains in uniform motion except an external force has acted upon it eg a ball in stable motion doesn't move until one moves or kicks it

second law:the body acted upon by an external force gains a momentum which is directly proportional to the applied force and acts in the direction of the force

third law: to every action there is an equal and opposite reaction eg if u push someone the person moves backward away from you and not towards you

8 0
3 years ago
Read 2 more answers
A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the
Maurinko [17]

Answer:

(a). The decay constant is 1.55\times10^{-5}\ s^{-1}

The half life is 11.3 hr.

(b). The value of N₀ is 2.38\times10^{11}\ nuclei

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity R_{0}=10\ mCi

Time t_{1}=4\ hours

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

R=R_{0}e^{-\lambda t}

\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})

Put the value into the formula

\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})

\lambda=0.0000154\ s^{-1}

\lambda=1.55\times10^{-5}\ s^{-1}

We need to calculate the half life

Using formula of half life

T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}

Put the value into the formula

T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}

T_{\dfrac{1}{2}}=44.719\times10^{3}\ s

T_{\dfrac{1}{2}}=11.3\ hr

(b). We need to calculate the value of N₀

Using formula of N_{0}

N_{0}=\dfrac{3.70\times10^{6}}{\lambda}

Put the value into the formula

N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}

N_{0}=2.38\times10^{11}\ nuclei

(c). We need to calculate the sample's activity

Using formula of activity

R=R_{0}e^{-\lambda\times t}

Put the value intyo the formula

R=10e^{-(1.55\times10^{-5}\times30\times3600)}

R=1.87\ mCi

Hence, (a). The decay constant is 1.55\times10^{-5}\ s^{-1}

The half life is 11.3 hr.

(b). The value of N₀ is 2.38\times10^{11}\ nuclei

(c). The sample's activity is 1.87 mCi.

4 0
4 years ago
A bicycle wheel of radius 0.28 m rolls down a hill without slipping. Its linear velocity increases constantly from 0 to 8 m/s in
Marina86 [1]

Answer:

10.989 rad/s²

Explanation:

Angular Acceleration: This is the acceleration of a body that undergoes a circular motion. The S.I unit of angular acceleration is rad/s²

The expression for angular acceleration is given as

a = αr.............. Equation 1

Where a = linear acceleration, α = angular acceleration, r = radius.

make α the subject of the equation

α = a/r............. Equation 2.

But,

a = (v-u)/t ............. Equation 3

Where v = final velocity, u = initial velocity, t = time.

substitute equation 3 into equation 2

α = (v-u)/rt............ Equation 4

Given: v = 8 m/s, u = 0 m/s, r = 0.28 m, t = 2.6 s

Substitute into equation 4

α = (8-0)/(0.28×2.6)

α = 8/0.728

α = 10.989 rad/s²

5 0
3 years ago
Which element is most likely to have an oxidation number of +3?
Marina86 [1]

Answer:

A different answer to this is AI

Explanation:

4 0
3 years ago
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