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k0ka [10]
3 years ago
12

A stone is dropped from a 80m bridge. How long does it take to fall?

Physics
1 answer:
alexandr402 [8]3 years ago
7 0
Using equation you can solve
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Why do you think that some asteroids tumble end over end through space while other asteroids rotate around their axis?
olga2289 [7]
Imagine a lonely asteroid there in space, untouched, not rotating, just still. Then another asteroid passes by and comes into contact with that first asteroid. Upon collision, based on the conservation of elastic momentum, the asteroid that was once still moves; it may even spin if the incoming asteroid hit it at its side. Now asteroids have three angles or rotation (three dimensions): θ (theta - to the x-axis), φ (phi - to the y-axis), and let's say ψ (psi - to the z-axis). So these asteroids wobble through space, spinning like crazy.

I may have gone too in depth. Sorry, lol.
I hope this helped!
7 0
3 years ago
Speed of a train is 5m/s, find its value in km/hr.​
antiseptic1488 [7]

Answer: 18km/hr

0.005km/s

1 sec --> 0.005

3600sec --> 0.005*3600 is 18

So, 18km/hr

4 0
2 years ago
Read 2 more answers
A sheet of red paper will look black when illuminated with
vovikov84 [41]
It's cyan.  I believe it's because it has green and blue in it.
6 0
3 years ago
Read 2 more answers
Ralphie runs north 0.5 km, then turns east and runs 2.0 km, turns south and runs 1.5 km, turns west and runs another 1km. What i
Step2247 [10]

Answer:

I think its 2km

Explanation:

bc if u put it out on a graph, it would essentially take about 4 jumps to get to your ending point, and assuming each jumb was 0.5 km. But if u dont trust me look at another answer bc I dont know if thats right or not.

7 0
3 years ago
A basketball player standing under the hoop shoots the ball straight up with an initial velocity of v0Part (a) What is the maxim
Mama L [17]

Answer:

Maximum height will be h=\sqrt{\frac{v_0^2}{2g}}

Explanation:

We have given initial velocity through which basketball is thrown =v_0

Acceleration due to gravity =g\  m/sec^2

At maximum height velocity will be zero

So final velocity v = 0 m /sec

According to third equation of motion v^2=u^2+2gh

0^2=v_0^2-2gh ( Negative sign is due to upward acceleration )

h=\sqrt{\frac{v_0^2}{2g}}

6 0
3 years ago
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