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malfutka [58]
3 years ago
10

A mixture of 1.00g h2 and 1.00g he is placed in a 1.00l container at 27 celcius calculate the partial pressure of each gas and t

he total pressure
Physics
1 answer:
r-ruslan [8.4K]3 years ago
4 0
<span>PV = nRT moles of H2 = 1/2 = 0.5 moles of He = 1/4 =0.25 T = 273 + 27 partial pressure of H2 Px1 = 0.5x0.083x300 P=12.45 atmospheres PP of He px1 = 0.25x0.083x300 P =6 22 atmospheres Totla pressure = 6.22 + 12.45 = 18.68 atm</span>
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A sinusoidal transverse wave travels along a long, stretched, string. the amplitude of this wave is 0.0885 m, it's frequency is
timofeeve [1]

Answer:

(a) 0.177 m

(b) 16.491 s

(c) 25 cycles

Explanation:

(a)

Distance between the maximum and the minimum of the  wave = 2A ............ Equation 1

Where A = amplitude of the wave.

Given: A = 0.0885 m,

Distance between the maximum and the minimum of the wave = (2×0.0885) m

Distance between the maximum and the minimum of the wave = 0.177 m.

(b)

T = 1/f ...................... Equation 2.

Where T = period, f = frequency.

Given: f = 4.31 Hz

T = 1/4.31

T = 0.23 s.

If 1 cycle pass through the stationary observer for 0.23 s.

Then, 71.7 cycles will pass through the stationary observer for (0.23×71.7) s.

= 16.491 s.

(c)

If  1.21 m contains  1 cycle,

Then, 30.7 m will contain (30.7×1)/1.21

= 25.37 cycles

Approximately 25 cycles.

6 0
3 years ago
The wavelength of red light is 7 x 10^-7 meter. Express this value in nanometers
3241004551 [841]

  • The wavelength of the red light in "nanometer" is 7× 10^{2}

  • Wavelength is given as : 7×10^{-7} meter

  • 1 nanometer = (10^{-9} meter)

  • Let X= value of the wavelength in nanometer.

1 nanometer  = 10^{-9} meter

X nanometer = 7× 10^{-7}  meter

  • <em>If we Cross multiply</em>

X nanometer = (\frac{     7* 10^{-7} }{  10^{-9} })

X= 7×10^{2} nanometer

Therefore, the wavelength in "nanometer" is 7×10^{2}

Learn more at :brainly.com/question/12924624?referrer=searchResults

6 0
3 years ago
Light of wavelength 400 nm is incident on a single slit of width 15 microns. If a screen is placed 2.5 m from the slit. How far
olganol [36]

Answer:

0.0667 m

Explanation:

λ = wavelength of light = 400 nm = 400 x 10⁻⁹ m

D = screen distance = 2.5 m

d = slit width = 15 x 10⁻⁶ m

n = order = 1

θ = angle = ?

Using the equation

d Sinθ = n λ

(15 x 10⁻⁶) Sinθ = (1) (400 x 10⁻⁹)

Sinθ = 26.67 x 10⁻³

y = position of first minimum

Using the equation for small angles

tanθ = Sinθ = y/D

26.67 x 10⁻³ = y/2.5

y = 0.0667 m

5 0
3 years ago
A solenoid is designed to produce a magnetic field of 3.50×10^−2 T at its center. It has a radius of 1.80 cm and a length of 46.
Anna11 [10]

Answer:

a. 2143 turns/m

b. 111.5 m

Explanation:

a. The minimum number of turns per unit length (N/L) can be found using the following equation:

B = \frac{\mu_{0}NI}{L}

\frac{N}{L} = \frac{B}{\mu_{0}I} = \frac{3.50 \cdot 10^{-2} T}{4\pi \cdot 10^{-7} Tm/A*13.0 A} = 2143 turns/m

Hence, the minimum number of turns per unit length is 2143 turns/m.

b. The total length of wire is the following:

N = 2143 turns/m*L = 2143 turns/m*46.0 \cdot 10^{-2} m = 986 turns

Since each turn has length 2πr of wire, the total length is:

L_{T} = N*2\pi r = 986 turn*2*\pi*1.80 \cdot 10^{-2} m = 111.5 m

Therefore, the total length of wire required is 111.5 m.

I hope it helps you!

4 0
3 years ago
What information can be determined by observing dark lines within the spectrum of a given star?
Scrat [10]
I believe the answer is D.  
6 0
3 years ago
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