What is the quotient (6x4 + 15x3 − 2x2 + 10x − 4) ÷ (3x2 + 2)?
2 answers:
Answer:
Step-by-step explanation:
÷ (3x2 + 2)
To divide it we use long division
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The given problem is :
(6x^4 + 15x^3 − 2x^2 + 10x − 4) ÷ (3x^2 + 2)?
now we can write expression (6x^4 + 15x^3 − 2x^2 + 10x − 4) as
(6x^4 + 4x^2 + 15x^3 + 10x - 6x^2 -4)
we have somehow arrange the expression in a way that 3x^2 + 2 is common
now the expression comes out to be
2x^2(3x^2 + 2) + 5x(3x^2+2) -2(3x + 2) / (3x^2+2)
After dividing final result comes out to be (2x^2 + 5x -2)
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Answer: 14
Step-by-step explanation:
Answer:
13
Step-by-step explanation:
h = 8
j = 11
3h - j
= 3(8) - 11
= 24 - 11
= 13
To find the diameter of the radius you need to multiply 3.5 x 2 = 7
Answer:
-7
Step-by-step explanation:
-3-(-10)/-2+1
-3-5+1
-8+1
-7
Answer:
must be greater than 7
Step-by-step explanation:
using pythagoras theorem
a^2=b^2-c^2
x^2=15^2-12^2
x^2=225-144
x^2=81
take square root both sides
√x^2=√81
x=9
and 9 is greater than 7