False, ex: 18/2 = 9
false, ex: 18/2 = 9
Answer: 75% Of the original price
Step-by-step explanation:
For this case we have that a quadratic equation is of the form:![ax ^ 2 + bx + c = 0](https://tex.z-dn.net/?f=ax%20%5E%202%20%2B%20bx%20%2B%20c%20%3D%200)
Where:
a: is the main coefficient because it accompanies the quadratic variable.
b: It is the linear coefficient
c: It is the constant term.
Then, a quadratic function with a main coefficient of "3" and a constant term of "-12" is:
![f (x) = 3x ^ 2 + 11x-12](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%203x%20%5E%202%20%2B%2011x-12)
Answer:
Option B
![f (x) = 3x ^ 2 + 11x-12](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%203x%20%5E%202%20%2B%2011x-12)
Answer:
<h2>6</h2>
Step-by-step explanation:
We know:
If a ≤ b ≤ c are the sides of a triangle, then a + b > c.
We have a = x, b = 2x and c = 15 cm.
Therefore x ≤ 15 and 2x ≤ 15 ⇒ x ≤ 7.5
Therefore we have the inequality:
x + 2x > 15
3x > 15 <em>divide both sides by 3</em>
x > 5 and x ≤ 7.5
Finally x = 6
Answer:
27mi
Step-by-step explanation:
Since the sailing course is equilateral in shape, then all their sides are equal.
Get one of the sides using Pythagoras theorem as shown;
Let one of the side be x
Two base will be x/2
According to the theorem;
x² = 9² +(x/2)²
x² = 81 + x²/4
x²-x²/4 = 81
3x²/4 = 81
3x² = 324
x² = 324/4
x² = 81
x = 9
Perimeter of the triangle = 3x
Perimeter of the triangle = 3(9)
Perimeter of the triangle = 27mi