Question

A plane is at cruising altitude of 10,200 feet. If the angle of depression to the run way is 18 degrees, what is the distance, to the nearest foot, from the plane to the run way

Answer 1

Answer: $33,007.9\ ft$

Step-by-step explanation:

Given

The plane is cruising at an altitude of $h=10,200\ ft$

The angle of depression is $\theta=18^{\circ}$

Suppose the distance of the plane to the runway is x

from figure

$\Rightarrow \sin 18^{\circ}=\dfrac{h}{x}\\\\\Rightarrow \sin 18^{\circ}=\dfrac{10,200}{x}\\\\\Rightarrow x=33,007.9\ ft$