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Darya [45]
3 years ago
8

A plane is at cruising altitude of 10,200 feet. If the angle of depression to the run way is 18 degrees, what is the distance, t

o the nearest foot, from the plane to the run way
Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer: 33,007.9\ ft

Step-by-step explanation:

Given

The plane is cruising at an altitude of h=10,200\ ft

The angle of depression is \theta=18^{\circ}

Suppose the distance of the plane to the runway is x

from figure

\Rightarrow \sin 18^{\circ}=\dfrac{h}{x}\\\\\Rightarrow \sin 18^{\circ}=\dfrac{10,200}{x}\\\\\Rightarrow x=33,007.9\ ft

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