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3 years ago

1.5 atm is the same pressure as... (1 atm 760 mmHg)

Chemistry

1 answer:

Darina [25.2K]3 years ago

3 0

<h3>Answer:</h3>

1100 mmHg

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

Pressure

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.5 atm

[Solve] mmHg

<u>Step 2: Identify Conversions</u>

1 atm = 760 mmHg

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.5 \ atm(\frac{760 \ mmHg}{1 \ atm})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1140 \ mmHg$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1140 mmHg ≈ 1100 mmHg

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svlad2 [7]

Lower flammable limit means the lowest concentration of a material that will propagate a flame.

What is hazardous atmosphere?

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What is lower flammable limit?

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1 year ago

Help me please i need the answer now<br>(nonsense report)

rusak2 [61]

Answer:

Quantitative

Words, Measurement, Numbers, Charts, Instruments, Quantity, Data

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Touch, Quality, Hear, Senses, Description, Exact, Narrative, Analyze

Explanation :

Quantitative Data

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3 years ago

The density of water at 400C is 0.992 g/mL What is the volume of 27.0 g of water at this temperature?

pantera1 [17]

Answer:

Volume of water at this temperature is 27.2 mL

Explanation:

We know that $density=\frac{mass}{volume}$

Here density of water is 0.992 g/mL

Here mass of water is 27.0 g

So $volume=\frac{mass}{density}$

= $\frac{27.0g}{0.992g/mL}$

= 27.2 mL

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3 years ago

how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate

Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

$3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3$

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

$0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})$

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

$63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})$

= $95.7gNaClO_3$

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate and then the grams are converted to kg.

$95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})$

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

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3 years ago

A cup of coffee has 71 mL of coffee and 127 mL of water. What is the percent volume of the coffee solution?

Anna [14]

Answer:

35.9%

Explanation:

The percent volume of the coffee solution can be calculated as follows:

% volume of coffee solution = volume of coffee/total volume of coffee solution × 100

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71mL + 127mL = 198mL

% volume = 71/198 × 100

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Percent volume of coffee solution = 35.9%

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3 years ago