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mina [271]
3 years ago
6

Balance the equations

Chemistry
1 answer:
OLga [1]3 years ago
3 0

Answer: a) H_3PO_4+3NaOH\rightarrow Na_3PO_4+3H_2O

b) PCl_3+3H_2O\rightarrow P(OH)_3+3HCl

c) 2Al+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.

The balanced chemical equations are :

H_3PO_4+3NaOH\rightarrow Na_3PO_4+3H_2O

PCl_3+3H_2O\rightarrow P(OH)_3+3HCl

2Al+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2

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vazorg [7]

Answer:

D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

Explanation:

Step 1: Detemine the mass of O in SO₂

There are 2 atoms of O in 1 molecule of SO₂. Then,

m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g

Step 2: Determine the mass of SO₂

m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g

Step 3: Detemine the mass percent of oxygen in SO₂

We will use the following expression.

m(O)/m(SO₂) × 100%

(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

5 0
3 years ago
Mercury’s natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) c
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Hope it helps...

Regards;

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3 0
3 years ago
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A sample of gas occupies 10.0 L at 240°C under a pressure of
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Answer: 1090°C

Explanation: According to combined gas laws

(P1 × V1) ÷ T1 = (P2 × V2) ÷ T2

where P1 = initial pressure of gas = 80.0 kPa

V1 = initial volume of gas = 10.0 L

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P2 = final pressure of gas = 107 kPa

V2 = final volume of gas = 20.0 L

T2 = final temperature of gas

Substituting the values,

(80.0 kPa × 10.0 L) ÷ (513 K) = (107 kPa × 20.0 L) ÷ T2

T2 = 513 K × (107 kPa ÷80.0 kPa) × (20.0 L ÷ 10.0 L)

T2 = 513 K × (1.3375) × (2)

T2 = 1372.275 K

T2 = (1372.275 - 273) °C

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8 0
3 years ago
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Predict the bond polarity of the following bonds:
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CH is nonpolar
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3 years ago
Explain why we dissected the eggs that didn't hatch. What was the outcome of our dissection? PLEASE HELP DUE TONIGHT
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It helps us develop our obervation skills and we learn what the egg looks like. We can learn the nutritional values of the egg.

Explanation:

Hope that helped

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