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3 years ago

What will happen to the chemical equilibrium if MgCl2 is added? PLEASE HURRY

Chemistry

2 answers:

vlabodo [156]3 years ago

8 0

Answer:

A!!!!

Just took the test!!!

Explanation:

kari74 [83]3 years ago

5 0

Answer:

Explanation:

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Chemistry!! Please help!!

cluponka [151]

Answer:

4.993 ×10⁻¹¹ J

Explanation:

The nuclear binding energy is the energy equivalent to the mass defect.

The mass defect is the difference between the mass of a nucleus and the sum of the masses of its nucleons.

Calculate the mass defect

16 p = 16 × 1.007 28 u = 16.116 48 u

16 n = 16 × 1.008 67 u = 16.138 72 u

Total mass of nucleons = 32.255 20 u

- Mass of S-32 = 31.972 070 u

Mass defect = 0.283 13 u

Convert the unified atomic mass units to kilograms.

Mass defect

$= \text{0.283 13 u} \times \frac{ \text{1.66 06} \times 10^{-27} \text{ kg}}{\text{1 u}}$

$= 4.700 \times 10^{-28} \text{ kg}$

Use Einstein’s equation to convert the mass defect into energy

$E = mc^{2}$

$E = 4.7000 \times 10^{-28} \text{ kg} \times (2.998 \times 10^{8} \text{ m}\cdot\text{s}^{-1})^{2} = 4.224 \times 10^{-11} \text{ J}$

4 0

3 years ago

How many grams in 4.53 moles of MgBr2

musickatia [10]

Answer:

520.12554

Explanation:

8 0

3 years ago

Which characteristic do electronegativity differences indicate about reactions between atoms

emmasim [6.3K]

O valence electron number is the answer

6 0

3 years ago

A measurement 172.54 m rounded to three significant figures is

xxTIMURxx [149]

173.00m
Step by step explanation
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6 0

3 years ago

One of the compounds used to increase the octane rating of gasoline is toluene (pictured). Suppose 43.3 mL of toluene (d = 0.867

Thepotemich [5.8K]

Answer:

(A)

Density = Mass / Volume

Mass = Density × Volume

$= 0.867 g/mL \times 43.3mL = 37.5411 g Toluene$

$1C_6 H_5 CH_3 + 9 O_2 > 7 CO_2 + 4 H_2 O$

Mole ratio of toluene : Oxygen is 1 : 9

$37.5411 g \text { Toluene } \times \frac{1 \text {mol} \text {toluene}}{92 g \text { toluene}} \times \frac{9 {mol} O_{2}}{1 \text {mol} \text { toluene }} \times \frac{32 g O_{2}}{1 {mol} O_{2}}=117 g O_{2}(\text {Answer})$

(B)

1 mole of Toluene produces 7 moles of $CO_2$ gas and 4 moles of $H_2 O$ Vapour

So the mole ratio is 1 : 11

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene }} \times \frac{11 \mathrm{mol} \text { gas }}{1 \text { mol toluene }} $$\\\\=4.49 \text { mol gaseous products (Answer) } $$

(C)

1mole contains $6.022\times10^{23}$ molecules

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene}} \times \frac{4 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \text { toluene }} \times \frac{6.022 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}} $\\\\$=9.82 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O} \text { (Answer) } $$

6 0

4 years ago