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puteri [66]
3 years ago
8

What will happen to the chemical equilibrium if MgCl2 is added? PLEASE HURRY

Chemistry
2 answers:
vlabodo [156]3 years ago
8 0

Answer:

A!!!!

Just took the test!!!

Explanation:

kari74 [83]3 years ago
5 0

Answer:

a

Explanation:

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How many liters of radon gas would be in 3.43 moles at standard temperature and pressure (273 K and 100 kPa)?
MissTica

Answer: Option B. 76.83L

Explanation:

1 mole of a gas occupy 22.4L at stp. This implies that 1mole of Radon also occupy 22.4L at stp.

If 1 mole of Radon = 22.4L

Therefore, 3.43 moles of Radon = 3.43 x 22.4 = 76.83L

5 0
3 years ago
If a 60 kg dog is on a 15 kg sled is pushed with a force of 300 N, what will be dogs acceleration? A) 900 N B) 4 kg C) 4 m/s2 D)
stepan [7]
The answer is C because you have to find acceleration.
6 0
3 years ago
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jasenka [17]

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3 years ago
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Determine how many gmol, kmol, and lbmols there are in 50 kilograms of n-hexane.
Artist 52 [7]

Answer: 581 gmol

0.581 kmol

1.28\times 10^{-3}lbmol

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{50\times 1000g}{86g/mol}=581mol

1. The conversion for mol to gmol

1 mol = 1 gmol

581 mol= \frac{1}{1}\times 581=581gmol

2. The conversion for mol to kmol

1 mol = 0.001 kmol

581 mol= \frac{0.001}{1}\times 581=0.581kmol

3. The conversion for mol to lbmol

1 mol = 2.2\times 10^{-3}lbmol

581 mol= \frac{2.2\times 10^{-3}}{1}\times 581=1.28\times 10^{-3}lbmol

3 0
3 years ago
Consider a sample of helium and a sample of neon, both at 30.0°C and 1.5 atm. Both samples have a volume of 5.0 liters. Which st
Triss [41]

Answer:

A.

Explanation:

Using the ideal gas equation, we can calculate the number of moles present. I.e

PV = nRT

Since all the parameters are equal for both gases, we can simply deduce that both has the same number of moles of gases.

The relationship between the mass of each sample and the number of moles can be seen in the relation below :

mass in grammes = molar mass in g/mol × number of moles.

Now , we have established that both have the same number of moles. For them to have the same mass, they must have the same molar masses which is not possible.

Hence option A is wrong

7 0
3 years ago
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