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3 years ago

Given that m<6=72 and m<14=72 determine which lines are parallel

Mathematics

1 answer:

kakasveta [241]3 years ago

6 0

Answer:

Lines m and n are parallel.

Step-by-step explanation:

< 6 and < 14 are both equal to 72 degrees and they are corresponding angles for lines m and n.

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The area of the city of Vancouver is 115 km^2. if the shape of Vancouver is approximately a square, how wide is the city of Vanc

Dmitry [639]

Answer:

The wide of the city is 10.7km

Step-by-step explanation:

To solve this we first have to know the formula to calculate the area of a square

a = area = 115 km²

s = side

a = s * s

now we replace with the known values

115 km² = s * s

115 km² = s²

√(115 km²) = s

10.724km = s

Round to the nearest tenth

s = 10.724km = 10.7km

The wide of the city is 10.7km

5 0

3 years ago

One staple weighs 31 milligrams. If a box of staples holds 250 staples, how many grams of staples does the box hold?

lilavasa [31]

Answer:

7.75

Step-by-step explanation:

1 mg = 0.001 g

31 mg * 0.001 = 0.31 grams per staple

0.31 g * 250 = 7.75 grams per 250 staples

8 0

3 years ago

Read 2 more answers

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

Your bank account hos a bolance of -$17. You deposit $70. What is your new balance? Show work:

Norma-Jean [14]

Answer:

Step-by-step explanation:

70-17= 53

3 0

3 years ago

Read 2 more answers

Easy algebra! Please help! Will mark brainiliest!

Inessa [10]

Answer:

y = $97749e^{x}$

Step-by-step explanation:

a) Let Area be the independent variable and Price of the homes sold be dependent on the area.

Let x represents the area and y represents the price.

We will plot the data in excel using trend line function.

The model so obtained is:

y = $97749e^{0.00002x}$

Rounding values to the nearest hundredth, we get

y = $97749e^{x}$

8 0

3 years ago