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elixir [45]
3 years ago
5

the mean amount of money spent per week on gas by a sample of 25 drivers was found to be $57.00 with a standard deviation of $2.

36. assuming the population distribution is normally distributed construct and interpret a 90% confidence interval for the mean amount of money spent on Gas per week​
Mathematics
1 answer:
JulijaS [17]3 years ago
5 0

Answer:

See below

Step-by-step explanation:

To construct a confidence interval we use the following formula:

ci = (sample mean) +- z*(sd)/[n^(1/2)]

The sample mean is 57, the standard deviation is 2.36, n s 25 and z is the  upper (1-C)/2 critical value for the standard normal distribution. Here, as we want a confidence interval at a 90% we have (1-C)/2=0.05 we have to look at the 1-0.05=0.95 value at the normal distribution table, which is 1.65 approximately. Replacing all these values:

ci = 57 +- 1.65*(2.36)/[25^(1/2)]

ci = 57 +- 3.894*/(5) = 57 +- 0.78

ci => (56.22 , 57.78)

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Answer:

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Step-by-step explanation:

To write the factored form, multiply a*c from the standard form ax^2+bx+c. Here it is 4*1 = 4.

Then find factors of 4 that add to b=-4.

4: 1,2,4

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Split the middle term into -2x+-2x and factor by grouping.

4a^2-2a+-2a+1\\(4a^2-2a)+(-2a+1)\\2a(2a-1)-1(2a-1)\\(2a-1)(2a-1)


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Step-by-step explanation:

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