Answer:
Prokaryotic cell:
Prokaryotic cell do not have the nucleus and their DNA is present in the cytoplasm. The membrane bound cell organelle are absent in the prokaryotic cells. The ribosome of prokaryotic cell is 70'S. Transcription and translation is coupled in prokaryotic cells.
Eukaryotic cells:
Eukaryotic cell have well defined nucleus and their DNA is present inside the nucleus. The membrane bound cell organelle are present in the eukaryotic cells. The ribosome of eukaryotic cell is 80'S. Transcription and translation is not coupled and takes place in separate compartments in eukaryotic cells.
The main parts of the brain involved in language processes are the Broca's area, located in the left frontal lobe, which is responsible for speech production and articulation, and the Wernicke's area, in the left temporal lobe, associated with language development and comprehension.
Answer:
If a DNA strand has the base sequence TTCCGGAA the complementary strand has the sequence AAGGCCTT.
Explanation:
A DNA molecule is constructed from sequences of its four nitrogenous bases: adenine, thymine, guanine and cytosine. Since DNA is made up of two strands, the sequence of nitrogenous bases of one strand is complementary to the other
.
The complementarity of the bases is a characteristic of the nitrogenous bases in the nucleic acids to combine with their complementary base, which is the same as saying that purines complement with pyramidines.
- <em>Adenine is combined with Thymine A=T
</em>
- <em>Cytosine is complemented with Guanina C≡G
</em>
In this way, given a sequence on a DNA strand
:
<em> T-T-C-C-G-G-A-A</em>
The complementary strand will have this sequence:
<em> A-A-G-G-C-C-T-T</em>
Biologists study cells due to the cell relation to that of animal cell
<h3>What are yeasts?</h3>
Yeast are eukaryotic organisms which are part of the fungus kingdom.
They are important to biologist because they tend too carry out all the functions of the eukaryotic cells and they are known to be closely related to animals
Learn more on yeasts here: brainly.com/question/25088514
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The first geneticist has identified an obese allele that he or she believes to be recessive. We will define his or her allele as o1 and the normal allele as O1. The obese allele appears to be recessive based on the series of crosses he or she performed.
Cross 1 with possible genotype:
Obese (o1o1) × Normal (O1O1) F1 All normal (O1o1)
Cross 2 with possible genotypes:
F1 normal (Oo1) × F1 normal (O1o1) F2 8 normal (O1O1 and O1o1)
2 obese (o1o1)
Cross 3 with possible genotypes:
Obese (o1o1) × Obese (o1o1) All Obese (o1o1)
A second geneticist also finds an obese mouse in her colony and performs the same types of crosses, which indicate to her that the obese allele is recessive. We will define her obese allele as o2 and the normal allele as O2.
The cross of obese mice between the two different laboratories produced only normal mice. These different alleles are both recessive. However, they are located at different gene loci. Essentially, the obese mice from the different labs have separate obesity genes that are independent of one another.
The likely genotypes of the obese mice are as follows:
Obese mouse 1 (o1o1O2O2) × Obese mouse 2 (O1O1o2o2)
F1 All normal (O1o1O2o2)
