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Katena32 [7]
3 years ago
6

Find the eighth term of a geometric sequence for which a,3 = 35 and r= 7.​

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:  

588245.  

Step-by-step explanation:  

nth term = an = a1 r^(n-1)   where a1 = the first term  

a3 = 35 = a1  7^(3 - 1)  

35 = a1* 49  

a1 = 35/49 = 5/7  

So the 8th term = (5/7)* (7)^7

= 588245

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Simplify the following numerical expressions.
Aleksandr-060686 [28]

Answer:

|7| - 7 = 0

2|-7| =  14

(-7)^2 =  49

-7-|-7|=  -14

-7-1-71= -79

Step-by-step explanation:

3 0
3 years ago
There are 5 candy canes for every 9 presents. How many candy canes are there when there are 108 presents
Ksju [112]

Answer:

When there are 108 presents, there are 60 candy canes

Step-by-step explanation:

candy canes : presents = 5:9

5/9 = x/108

cross multiply:

(5) (108) = 9x

540 = 9x, divide both sides by 9

x = 60

5 0
2 years ago
4q=52 wats the answer to this equation ​
Darya [45]

4q=52

divide by 4 for both sides

4q/4= 52/4

q= 13

Answer : q=13

6 0
3 years ago
What is the value of 6 + 2x when x = 5?<br><br> (A) 4<br> (B) 13<br> (C)16<br> (D) 40
jasenka [17]

so x=5

substituting for x in the equation we get:

6+2 \times 5 \\  = 6 + 10 = \\  = 16

Ans C: 16

4 0
3 years ago
What is an equation of the line that passes through the points (-6, -2) and
den301095 [7]

Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

The equation of line in slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=-6,y_1=-2, x_2=-3, y_2=2

Putting values and finding slope

Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}

So, we get slope: m=\frac{4}{3}

Finding y-intercept

Using point (-6,-2) and slope m=\frac{4}{3} we can find y-intercept

y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

Now transforming in fully reduced form:

y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18

So, the equation of line is: \mathbf{4x-3y=-18}

6 0
2 years ago
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