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Eddi Din [679]
3 years ago
10

Write two division equations for each multiplication equation. 15⋅25=6 15 ⋅ 2 5 = 6 6⋅43=8 6 ⋅ 4 3 = 8 16⋅78=14

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

(a) \frac{30}{5} = 6 and \frac{60}{10} = 6

(b) \frac{24}{3} = 8 and \frac{96}{12} = 8

(c) \frac{112}{8} = 14 and \frac{28}{2} = 14

Step-by-step explanation:

Given

(a)\ 15 * \frac{2}{5} = 6

(b)\ 6 * \frac{4}{3} = 8

(c)\ 16 * \frac{7}{8} = 14

Required

Write 2 division equations

(a)\ 15 * \frac{2}{5} = 6

Express 15 as 15/1

\frac{15}{1} * \frac{2}{5} = 6

Multiply numerator and denominator

\frac{30}{5} = 6 --- This is (1)

Multiply the fraction by a common term (e.g. 2)

So, we have:

\frac{30*2}{5*2} = 6

\frac{60}{10} = 6 ---- (2)

(b)\ 6 * \frac{4}{3} = 8

Express 6 as 6/1

\frac{6}{1} * \frac{4}{3} = 8

Multiply numerator and denominator

\frac{24}{3} = 8 --- This is (1)

Multiply the fraction by a common term (e.g. 4)

So, we have:

\frac{24*4}{3*4} = 8

\frac{96}{12} = 8 ---- (2)

(c)\ 16 * \frac{7}{8} = 14

Express 16 as 16/1

\frac{16}{1} * \frac{7}{8} = 14

Multiply

\frac{112}{8} = 14 ---- This is (1)

Divide the fraction by a common term (e.g. 4)

\frac{112/4}{8/4} = 14

\frac{28}{2} = 14

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Complete Question

A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes. What equation can you use to find the distance of the flowerbed from the hive?

Answer:

The equation is 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

Step-by-step explanation:

From the question we are told that

The velocity of the bee is v =  9ft/s =

The duration on the flowerbed is t =  13 \  minutes  =  780 \  s

The velocity back to his hive is u = 6ft / s

The total time away from it hive is t_t  =  16 \  minutes  =  960  \ s

Now let assume the distance of the flower bed from the hive is Z

Generally the time taken for the bee to travel to the flower bed from its hive is

t_1 =  \frac{Z}{9}

The time taken for the bee to fly back to his hive is

t_2 =  \frac{Z}{6}

Generally the total time the bee spent outside of his house is mathematically represented as

t_t  =  t_1 + t_2 +  t

=> 960  = \frac{Z}{9}+ \frac{Z}{6} + 780

6 0
3 years ago
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