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Cloud [144]
3 years ago
11

When an oxygen atom forms an ion, it gains two electrons. Identify the electrical charge of the oxygen ion.

Chemistry
2 answers:
mel-nik [20]3 years ago
5 0
"-2" is the electric charge of the oxygen ion among the following choices given in the question. It actually needs two electrons to complete the stable outer shell. The correct option among all the options that are given in the question is the third option or option "C". I hope that the answer has helped you.
serg [7]3 years ago
5 0

-2 is the answer I believe

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The red arrow is pointed at different locations of an atom of Helium. Where is it pointing to the GREATEST concentration of atom
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Answer:

A is the correct answer.

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

For example  in case of Helium:

The 1st one diagram shows that arrow is pointing with in nucleus. The helium nucleus contain two protons and two neutrons. Thus maximum mass is present with in nucleus. while two electrons are revolve around the nucleus and mass of electron is negligible.

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3 years ago
What happens when you put magnesium carbonate and diluted water
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Answer:

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Explanation:

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8 0
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Ou have a 5 ml sample of a protein in 0.5 m nacl. you place the protein/salt sample inside dialysis tubing (see fig. 2-14) and p
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Answer:

Procedure (2)  

Explanation:

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Procedure (1)

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\dfrac{5}{4000} = \dfrac{1}{800}

Procedure (2)

For the first dialysis, the factor is

\dfrac{5}{1000} = \dfrac{1}{200}

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Procedure (2) is more efficient by a factor of  

\dfrac{40000}{800} = \mathbf{50}

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