Hey there!:
Balanced equation:
F2(g) + CaBr2(s) ---> CaF2 + Br2
1 mol F2 = 1 mol CaBr2
Calculation:
2.31 g CaBr2
* (1 mol CaBr2 / 199.886 g CaBr2) * (1 mol F2 / 1 mol CaBr2)
= 0.0115565 moles of F2:
Assuming F2 is an ideal
gas at these conditions:
P*V = n*R*T
Solving for V:
V = (n *R* T) / P
where :
n = 0.0115565 moles
R = 0.08206 atm·L/mol·K
Temperature in K = 35 + 273.15 => 308.15 K
P = 8.19 atm
Substituting numbers into V = (n x R x T) / P:
V = 0.0115565 * 0.08206 * 308.15 / 8.19
V = 0.29222 / 8.19
V = 0.0357 or 3.57*10⁻² L
You are correct!!!
Hope that helps!
Answer:
Try:
1. How many atoms are in 6.5 moles of zinc?
6.5 moles 6.02 x 1023 atoms = 3.9 x 1024 atoms
1 mole
2. How many moles of argon are in a sample containing 2.4 x 1024 atoms of argon?
2.4 x 1024 atoms of argon 1 mole = 4.0 mol
6.02 x 1023 atoms
3. How many moles are in 2.5g of lithium?
2.5 grams Li 1 mole = 0.36 mol
6.9 g
4. Find the mass of 4.8moles of iron.
4.8 moles 55.8 g = 267.84 g = 270g
1 mole
Explanation:
i think i did it about right..?? :-(
Answer:
it will explod because off all of the prussere but on to it.
Explanation:
Answer: False
Explanation: Solutions can never be Heterogenous
