Explanation:
Copper sulphate reacts with potassium iodide to form cuprous iodide and iodine.
2CuSO
4
+4KI→Cu
2
I
2
↓+I
2
+2K
2
SO
4
Thus, CuI
2
is not formed in this reaction.
Hence, the option B is incorrect and option A is correct.
The liberated iodine is titrated with sodium thiosulphate to form sodium tetrathionate.
2Na
2
S
2
O
3
+I
2
→Na
2
S
4
O
6
+2NaI
Iodine is reduced and sodium thiosulphate is oxidized.
Given :
A balanced chemical equation :
To Find :
How many grams of zinc are needed to produce 12 grams of zinc chloride.
Solution :
Moles of 
,
Now, by balanced chemical equation we can say that 1 mol of Zn produce
1 mol of .
So, 0.088 mol of Zn is required to produced 0.088 mol of .
Therefore, 5.8 grams of zinc is required.
Hence, this is the required solution.
Answer: The molarity of the base solution is 0.22 M.
Explanation:
According to the neutralization law,
where,
= molarity of 
solution = 0.1994 M
= volume of solution = 38.87 ml
= molarity of 
solution = ?
= volume of solution = Final reading - Initial reading = 36.18 - 1.16 = 35.02 ml
= valency of = 1
= valency of = 1
Therefore, the molarity of the base solution is 0.22 M.
Answer:
20.5 × 10²³ molecules of He
Explanation:
Given data:
Number of moles of He = 3.40 mol
Number of molecules of He = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 3.40 moles of He:
3.40 mol × 6.022 × 10²³ molecules
20.5 × 10²³ molecules of He
Answer:
393.1 KPa
Explanation:
Now we have to use the general gas equation;
P1V1/T1 = P2V2/T2
P1= initial pressure of the gas= 1.00atm
V1 = initial volume= 700.0 ml
T1= initial temperature= 0.0°C +273= 273K
V2= final volume= 200.0 ml
T2= final temperature =30.0°C +273= 303 K
P2= final pressure =????
Therefore;
P2= P1V1T2/ V2T1
P2= 1.00 × 700.0 × 303/ 200.0 × 273
P2= 3.88 atm
But
1 atm = 101.325 kilopascals
Therefore 3.88 atm = 3.88 × 101.325 kilopascals = 393.1 KPa
