What is the minimum or maximum value of the equation of this equation? f(x) = -(x-8)^2 -30
1 answer:
9514 1404 393
Answer:
f(8) = -30 is the maximum
Step-by-step explanation:
The equation is that of a parabola in vertex form:
y = a(x -h)^2 +k . . . . . . . . (h, k) is the vertex; 'a' is the scale factor
Comparing this form to the given equation, we have ...
f(x) = -(x -8)^2 -30
- a = -1
- h = 8
- k = -30
That is, the scale factor is -1, and the vertex is (8, -30).
When the scale factor is negative, the graph opens downward and the vertex is a maximum. The maximum value is -30.
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Answer:
142.932
Step-by-step explanation:
given that in triangle ABC, AC =24
Angle A = 30 and Angle B =45
If we draw altitude from C, we get
h = 24sin 30 = 12
Since BC = h (45, 45,90 triangle)
BC=12
By sine formula for triangle
Area of triangle
=