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2 years ago

12

Mrs. Soto invested in a certificate of deposit that pays 8% interest. Her investment was $325. How much interest will she receiv

e in 1 year

2 answers:

sesenic [268]2 years ago

4 0

Answer: SHE receive in 1 year is 325.08

Step-by-step explanation: it is basically adding so u add 8%+325 =325.08

brilliants [131]2 years ago

3 0

Answer:

Answer 1.

If the interest is yearly she will have 351$ / she made 26 dollars in interest.

Step-by-step explanation:

Answer 1.

We multiply 325 times .08 which is equal to 8%, that gives us 26 and from there we add 325 which equals 351$ (if you want to make is simpler multiply by 1.08 eliminating the need to add the original sum again).

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An equation is shown below:

Dahasolnce [82]

Part A: first multiply 2 by x and -3, then combine the like terms, after that add 6 from both sides, then subtract 6x from both side, the answer is -5.
4x + 2(x-3) = 4x + 2x - 11
4x +2x -6 = 4x + 2x - 11
6x -6 = 6x - 11
6x = 6x -11 +6
6x = 6x -5
6x-6x= -5
0 = -5
part B) add the like terms

7 0

2 years ago

Read 2 more answers

As an estimation we are told £3 is €4.<br> Convert £18 to euros.

Yuri [45]

Answer:

€24

Step-by-step explanation:

We can use ratios to solve this.

3:4 = 18:x

Cross multiply: 3x = 18*4

Divide: x = 18*4/3

Simplify: x = 6*4 = 24

5 0

1 year ago

What is Factor 64b-16c to identify the equivalent expressions.

liubo4ka [24]

Answer:
16(4b - c)

Explanation:
16 x 4b = 64b
16 x c = 16c

3 0

3 years ago

Find two vectors in R2 with Euclidian Norm 1<br> whoseEuclidian inner product with (3,1) is zero.

alina1380 [7]

Answer:

$v_1=(\frac{1}{10},-\frac{3}{10})$

$v_2=(-\frac{1}{10},\frac{3}{10})$

Step-by-step explanation:

First we define two generic vectors in our $\mathbb{R}^2$ space:

$v_1 = (x_1,y_1)$
$v_2 = (x_2,y_2)$

By definition we know that Euclidean norm on an 2-dimensional Euclidean space $\mathbb{R}^2$ is:

$\left \| v \right \|= \sqrt{x^2+y^2}$

Also we know that the inner product in $\mathbb{R}^2$ space is defined as:

$v_1 \bullet v_2 = (x_1,y_1) \bullet(x_2,y_2)= x_1x_2+y_1y_2$

So as first condition we have that both two vectors have Euclidian Norm 1, that is:

$\left \| v_1 \right \|= \sqrt{x^2+y^2}=1$

and

$\left \| v_2 \right \|= \sqrt{x^2+y^2}=1$

As second condition we have that:

$v_1 \bullet (3,1) = (x_1,y_1) \bullet(3,1)= 3x_1+y_1=0$

$v_2 \bullet (3,1) = (x_2,y_2) \bullet(3,1)= 3x_2+y_2=0$

Which is the same:

$y_1=-3x_1\\y_2=-3x_2$

Replacing the second condition on the first condition we have:

$\sqrt{x_1^2+y_1^2}=1 \\\left | x_1^2+y_1^2 \right |=1 \\\left | x_1^2+(-3x_1)^2 \right |=1 \\\left | x_1^2+9x_1^2 \right |=1 \\\left | 10x_1^2 \right |=1 \\x_1^2= \frac{1}{10}$

Since $x_1^2= \frac{1}{10}$ we have two posible solutions, $x_1=\frac{1}{10}$ or $x_1=-\frac{1}{10}$ . If we choose $x_1=\frac{1}{10}$ , we can choose next the other solution for $x_2$ .

Remembering,

$y_1=-3x_1\\y_2=-3x_2$

The two vectors we are looking for are:

$v_1=(\frac{1}{10},-\frac{3}{10})\\v_2=(-\frac{1}{10},\frac{3}{10})$

5 0

2 years ago

Find the missing length in the image below

lara31 [8.8K]

Let it be x

Using basic proportionality theorem

$\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{14}{7}$

$\\ \sf\longmapsto \dfrac{x}{10}=2$

$\\ \sf\longmapsto x=10(2)$

$\\ \sf\longmapsto x=20$

7 0

2 years ago