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Mice21 [21]
2 years ago
11

Proposition 2.30. Suppose X and Y are topological spaces, and f : X → Y is any map. (a) f is continuous if and only if f (A c f(

A) for all ASX. (b) f is closed if and only if f (A) 2 f(A) for all A CX. (c) f is continuous if and only if f -(Int B) Intf-?(B) for all B CY. (d) f is open if and only if f-'(Int B) 2 Int f-'(B) for all B C Y.
Mathematics
1 answer:
V125BC [204]2 years ago
4 0

Answer:

54

Step-by-step explanation:

lkjiuyog

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Hector is flying a kite. He has let out 86 feet
Kaylis [27]

Answer:

Hector's kite is 61.84 feet from the ground.

Step-by-step explanation:

The angle of elevation of the kite is 42°15’30” when converted to decimals, it is 42.258333^{0} ≅ 42.26^{0}

Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,

Sin θ = \frac{opposite}{hypotenus}

Sin 42.26^{0} = \frac{x}{86}

⇒ x = 86 x Sin 42.26^{0}

      = 86 x 0.6725

     = 57.835

x ≅ 57.84 feet

The height of Hector's kite from the ground = x + 4

                                    = 57.84 + 4

                                   = 61.84 feet

7 0
3 years ago
In 6^3 what is the 3 called?
Musya8 [376]

Answer:

its an exponent

Step-by-step explanation:

6 0
3 years ago
There are 4 consecutive even integers that add up to 268. Which integers are they?
xz_007 [3.2K]

Answer:

4n+ 12 = -268, or 4n = -280, or n = -70. This would imply that the four consecutive ODD integers are -70, -68, -66, -64.

Step-by-step explanation:

Hope this helps         :)

4 0
3 years ago
Limx→+∞​ (x-(lnx)^2) =?​
expeople1 [14]

\lim_{x\to\infty}(x-\ln(x)^2) \\\lim_{x\to\infty}(x-2\ln(x)) \\\lim_{x\to\infty}\Big(x\Big(1-\dfrac{2\ln(x)}{x}\Big)\Big) \\\lim_{x\to\infty}x\cdot\lim_{x\to\infty}\Big(1-\dfrac{2\ln(x)}{x}\Big) \\\infty\cdot\Big(\lim_{x\to\infty}(1)-\lim_{x\to\infty}\Big(\dfrac{2\ln(x)}{x}\Big)\Big) \\\infty\cdot(1-2\lim_{x\to\infty}(1/x)) \\\infty\cdot(1-0) \\\infty\cdot1=\boxed{\infty}

Hope this helps.

3 0
3 years ago
find the area and perimeter of a rectangle with a width of 2 1/3inch and a length of 5 2/5inches. show your work please.
aleksandrvk [35]
Area: If you multiply 2 1/3 by 5 2/5, you get an answer of about: 12.6, which means the area is about: 12.6in. squared.
Perimeter: If you add 2 1/3+ 2 1/3+ 5 2/5+ 5 2/5 you get an answer of about: 15.47. So, the perimeter is about 15.47in.

Note: If you aren't allowed to use a calculator on this test, you should probably multiply the numbers yourself so you get show the work and get the answer in a fraction, which is probably what they want. If you are allowed to use calculators, all the information you need is right here.
4 0
2 years ago
Read 2 more answers
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